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2 years ago

Help me plz STEP BY STEP PLZ!!!

Mathematics

1 answer:

lidiya [134]2 years ago

6 0

Answer:

Step-by-step explanation:

So basically first multiply the cups of clean total by 2 so it would equal 4 cups. This mean you would have 2/4 of white vinegar. Then divide the equation by 2 because we need 5 cups not 6 of spray. To have half of 1/4 we need to do 1/8 which is half of 1/4. Then we convert the first 2/4 by dividing by 2 and get 5/8.

IK this explanation isn't the best but hopefully it helps

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PLZ HELPPPP!!!!!!! EASY 10 POINTS *easy*

mars1129 [50]

Answer:

dialation

Step-by-step explanation: can i hve brainiliest

4 0

3 years ago

Read 2 more answers

Helppppppppppp:)))))))))

Whitepunk [10]

Hi there!

We are given the set of ordered pairs below:

$\large \boxed{(3, - 1),(2, - 2),(0,2),(2,1)}$

1. What is the domain?

Domain is a set of all x-values in one set of ordered pairs. So what are the x-values that I am talking about? In ordered pairs, we define x and y which both have relation to each others which we can write as (x,y). That's right, the domain is set of all x-values from ordered pairs.

Therefore, we gather only x-values from (x,y). Hence, the domain is {3,2,0,2}. Whoops! Something is not right. As we learn in Set Theory that we don't write the same or repetitive in a set. Hence, the actual domain is {0,2,3}

2. What is the range?

Because domain is set of all x-values. Then what do you think the range is? That's right! The range is set of all y-values. If you got this right before looking up the underlined words then a handclap for you! So how do we find range? Simple, we just do like finding the domain in the Q1, except we gather the y-values in (x,y) instead and make sure that we don't write same number!

Therefore, gather y-values from the ordered pairs. Hence, the range is {-2,-1,1,2}

3. Is the relation a function?

All functions are relations but not all relations are functions. Function is a set of ordered pairs where domain is not repetitive or in a set, there cannot be more than one same value. Consider the following relation: (1,1),(1,2) - Oh, looks like in a set of ordered pairs, there are two same domains which make it only a relation, and not a function. On the other hand, (1,1),(2,2) - Looking good! No same or repetitive domain, making it indeed a function.

Consider the domain from Q1 and see if there are two same values of x in a set. Looks like the relation is not a function since there are same x-values which are 2 in a set, making it only a relation. Hence, the relation is not a function.

These are all 3 answers along with an explanation. Let me know if you have any doubts regarding Relations and Functions.

From the Q1's answer, there are two bold texts, please choose the second bold text to answer (the one with underline) and not the first one (the one with same 2's).

Good luck on your assignment, have a nice day!

4 0

3 years ago

Match the products of rational expressions with their simplest forms.

Alborosie

Lets simplify each one of the rational expressions using the product rule of exponents: $a^n*a^m=a^{n+m}$ and the quotient rule of exponents: $\frac{a^n}{a^m} =a^{n-m}$ .

1. $\frac{-3x^2}{2y^2} * \frac{y^2}{9x} =- \frac{x}{6} = \frac{-1}{6} x$

2. $\frac{5y^2}{10x^2} * \frac{4x^2}{y} =2y$

3. $\frac{-9y^2}{5x} * \frac{-10x^2}{3y} =6xy$

4. $\frac{14x^2}{5y} * \frac{-10y}{7x} =-4x$

We can conclude that you should pair the rational expressions with their simplest form as follows:
$6xy-----\ \textgreater \ \frac{-9y^2}{5x} * \frac{-10x^2}{3y}$
$\frac{-1}{6} x-----\ \textgreater \ \frac{-3x^2}{2y^2} * \frac{y^2}{9x}$
$-4x-----\ \textgreater \ \frac{14x^2}{5y} * \frac{-10y}{7x}$
$2y-----\ \textgreater \ \frac{5y^2}{10x^2} * \frac{4x^2}{y}$

7 0

3 years ago

Guys i have 2 min whats the answer?

Aleks04 [339]

Step-by-step explanation:

4 tubes connected vertically.

each tube is 0.28 meters long.

it does not leave me any other form of interpretation than just to stack the tubes on top of each other.

4×0.28 = 1.12 meters

6 0

3 years ago

Estela and Gavin make a poster together. Estela asks Gavin to draw a quadrilateral

kykrilka [37]

Answer: The diagonals of a parallelogram bisect each other. Steps (a), (b), and (c) outline proof of this theorem. (See Exercise 25 for a particular instance of this theorem.) (a) In the parallelogram OA BC shown in the figure, check that the coordinates of must be (b) Use the midpoint formula to calculate the midpoints of diagonals and (c) The two answers in part (b) are identical. This shows that the two diagonals do indeed bisect each other, as we wished to prove. (FIGURE CAN'T COPY)

7 0

3 years ago