Electrical force between the two charges is (attractive)
Explanation:
The magnitude of the electrostatic force between two charged particles is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two particles
r is the separation between the two particles
In this problem, we have:
is the charge of the first particle
is the charge of the second particle
r = 3 m is the separation between them
Substituting into the formula, we find the force:
And the negative sign means the force is attractive (the electric force between two charges with opposite sign is attractive)
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Conduction is the transfer of heat without the actual motion of molecules and it takes place only in solids.
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Answer:
Option B. 28 N
Explanation:
From the question given above, the following data were obtained:
Coefficient of static friction (μ) = 0.35
Normal force (N) = 80 N
Frictional force (F) =?
The coefficient of static friction, frictional force and the normal force are related according to the following equation:
Coefficient of friction = frictional force / normal force
μ = F/N
With the above formula, we can obtain the frictional force as follow:
Coefficient of static friction (μ) = 0.35
Normal force (N) = 80 N
Frictional force (F) =?
μ = F/N
0.35 = F / 80
Cross multiply
F = 0.35 × 80
F = 28 N
Thus the frictional force is 28 N
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Your answer is B :) because well the conditions are harsh.