What is the density of a block of wood with a mass of 12g and a volume of 6 cm3?

Physics

1 answer:

scZoUnD [109]3 years ago

5 0

<h2>Answer: 2 g/cm³</h2>

Explanation:

Density = mass ÷ volume

= 12 g ÷ 6 cm³

= 2 g/cm³

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4 years ago

an input force of 50 Newtons is applied through a distance of 10 meters to machine with mechanical advantage of 3. If the work o

gladu [14]

The output of the machine is

(output work) = (output force) x (distance)

450 N-m = (output force) x (3 meters)

Divide each side
by 3 meters: Output force = (450 N-m) / (3 m)

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___________________________________

Well, my goodness !
I didn't even need to go through all of that.

Given:

-- The input force to the machine is 50 newtons.

-- The mechanical advantage of the machine is 3 .

That right there tells us that

-- The output force of the machine is 150 newtons.

We don't need any of the other given information.

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3 years ago

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Two spherical objects at the same altitude move with identical velocities and experience the same drag force at a time t. If Obj

Anna35 [415]

Answer:

<em>The object with the twice the area of the other object, will have the larger drag coefficient.</em>

Explanation:

The equation for drag force is given as

$F_{D} = \frac{1}{2}pu^{2} C_{D} A$

where $F_{D}$ IS the drag force on the object

p = density of the fluid through which the object moves

u = relative velocity of the object through the fluid

p = density of the fluid

$C_{D}$ = coefficient of drag

A = area of the object

Note that $C_{D}$ is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid

The above equation can also be broken down as

$F_{D}$ ∝ $P_{D}$ A