All categories

3 years ago

A team of scientists is working to determine if a meteor created a landform.

Physics

1 answer:

liubo4ka [24]3 years ago

3 0

Answer:

geology , astronomy

Explanation:

The earth science is a body of knowledge that includes the fields of the all the natural science as the geology, astronomy and those relate to the planet earth and hence deals with the physical and the chemical constitution and other includes the planetary science

<u>The study of the lithosphere, hydrosphere, and the biosphere and takes a holistic view of the earth.</u>

Thus for a team of contents that are working to locates and fond out the exact cause of the meteor that led to the formation of land-forms will relate to the application of the geology and the astronomy.

You might be interested in

A guitar player tunes the fundamental frequency of a guitar string to 560 Hz. (a) What will be the fundamental frequency if she

lawyer [7]

Answer:

(a) if she increases the tension in the string is increased by 15%, the fundamental frequency will be increased to 740.6 Hz

(b) If she decrease the length of the the string by one-third the fundamental frequency will be increased to 840 Hz

Explanation:

(a) The fundamental, f₁, frequency is given as follows;

$f_1 = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L}$

Where;

T = The tension in the string

μ = The linear density of the string

L = The length of the string

f₁ = The fundamental frequency = 560 Hz

If the tension in the string is increased by 15%, we will have;

$f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T\times 1.15}{\mu}} }{2 \cdot L} = 1.3225 \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = 1.3225 \times f_1$

$f_{(1 \, new)} = 1.3225 \times f_1 = (1 + 0.3225) \times f_1$

$f_{(1 \, new)} = 1.3225 \times f_1 =\dfrac{132.25}{100} \times 560 \ Hz = 740.6 \ Hz$

Therefore, if the tension in the string is increased by 15%, the fundamental frequency will be increased by a fraction of 0.3225 or 32.25% to 740.6 Hz

(b) When the string length is decreased by one-third, we have;

The new length of the string, $L_{new}$ = 2/3·L

The value of the fundamental frequency will then be given as follows;

$f_{(1 \, new)} = \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \times \dfrac{2 \times L}{3} } =\dfrac{3}{2} \times \dfrac{\sqrt{\dfrac{T}{\mu}} }{2 \cdot L} = \dfrac{3}{2} \times 560 \ Hz = 840 \ Hz$

When the string length is reduced by one-third, the fundamental frequency increases to one-half or 50% to 840 Hz.

6 0

3 years ago

At its natural resting length, a muscle is close to its optimallength for producing force. As the muscle contracts, the maximumf

lesantik [10]

Answer:

Figure E is the correct representation of the first part of the motion. When in a hanging position from the chin-up bar, the bicep muscles are stretched beyond their normal length already. So at this point they are at the peak of their capacity and you are at rest (this corresponds to the velocity v = 0 at t = 0). On contracting the bicep muscles and pulling your whole body up, you begin to gain speed and v increases. This increase in velocity is exponential. Soon the bicep muscles contract up to 80% their normal length reducing the force they can produce to keep you rising up to zero. The velocity change happens because the body is accelerating and the muscles can still supply a net force to lift you up. The acceleration is present because of this net force. The moment this force reduces to zero, the acceleration too reduces to zero. (From Newton's second law of motion). This reduction in acceleration is responsible for the reduction of the curvature of the v curve in figure E above. The point where the velocity becomes horizontal corresponds to the point where the muscles reach their maximum contraction unit and can supply no more net force and as a result no acceleration. This further results inba constant velocity which is the flat nature of the curve seen in diagram E.

Thank you for reading.

Explanation:

5 0

3 years ago

A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brak

mylen [45]

Answer:

final velocity = 0

because the train stoped

so,

acceleration = (v - u) ÷ t
acceleration = (0 - 22) ÷ 135
acceleration = -22 ÷ 135

acceleration = -0.162 m/s²

5 0

3 years ago

Calculate the force generated by a car that hits the wall at an

Makovka662 [10]

This is a defective question. It was WRITTEN by someone who is unclear on the concepts. DON'T try and answer it.

It's trying to get us to use Newton's second law ... F = m • a.

But that only tells us how much force must act ON THE CAR in order to accelerate it. (45 kg) • (4 m/s^2) = 180 newtons.

This is NOT the force exerted BY the car when it hits something. THAT force depends on its speed WHEN it hits, AND how long it takes for the wreckage to actually come to rest, AND how hard or soft the wall is.

DON'T try to answer this question. Your answer will be wrong, you won't understand why, and the teacher you try to argue with probably won't either.

============================================

More explanation:

Think about jumping off of a ladder in your back yard. Several times.

Your mass is the same every time. Your acceleration is the same every time . . . 9.8 m/s² down, the acceleration of Earth gravity, every time.

BUT ...

-- I'll bet you would rather land on wood than on concrete. The force of landing would be less.

-- I'll bet you would rather land on dirt than on wood. The force of landing would be less.

-- I'll bet you would rather land on grass than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a pile of blankets than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a trampoline than on a pile of blankets. The force of landing would be less.

-- I'll bet you would rather jump from a short ladder than from a tall one. Your speed would be less when you landed, and the force of landing would be less.

==> Your mass is the SAME every time, and your acceleration is the SAME every time. But the force when you hit is DIFFERENT every time.

The mass and acceleration of the car DON'T tell us the force of the hit when the car hits a wall.

6 0

3 years ago

For a closed system, entropy Group of answer choices may be produced within the system. all of the answers are correct. may be t

wolverine [178]

Answer:

The answer is: all of the answers are correct.

Explanation:

Entropy is defined as the magnitude of the irreversibilities of a process. Entropy is the disorder of molecules within a system. If the system is closed, entropy is produced if the process is irreversible. If the system is subjected to expansions or energy transfer, the entropy increases.

A process is reversible if the system and its surroundings are returned to their initial states. In a quasi-static process it is characterized by being a reversible process in which there are no irreversibilities. The entropy in this system is constant in the system.

6 0

3 years ago