Answer:
0.1426 = 14.26% probability that at least one of the births results in a defect.
Step-by-step explanation:
For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).
This means that 
A local hospital randomly selects five births.
This means that 
What is the probability that at least one of the births results in a defect?
This is:

In which



0.1426 = 14.26% probability that at least one of the births results in a defect.
What do the instructions say?
Answer:
2x+30=x+80 (corresponding angles)
2x-x=80-30
x=50
Answer:

Step-by-step explanation:
Notice that we are requested to perform a horizontal shift of on unit to the right. Recall that a horizontal shift of one unit to the right involves the operation of subtracting from the variable "x" one unit.
Therefore, this implies the following mathematical transformation to the variable "x":

where we simply completed distributive property to get rid of the parenthesis inside the absolute value.