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Lelechka [254]
3 years ago
7

Which undefined term can contain parallel lines?

Mathematics
1 answer:
dusya [7]3 years ago
6 0
Point I think is the anwser
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In the diagram the radius of the outer circle is 2x cm and the radius of the inner circle is 6 cm. The area of the shaded region
stich3 [128]

let's find the area of the outer circle and the inside circle

the inside's circle area

A= π x 6²=36π

the outer's

A' = π x 4x²= 4πx²

A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.

5 0
3 years ago
On babylonian tablet ybc 4652, a problem is given that translates to this equation: x x plus startfraction x over 7 endfraction
seraphim [82]

The correct option is (A). The solution of the equation is x=48.125.

Given an equation x+\frac{x}{7}+\frac{1}{11}\left(x+\frac{x}{7}\right)=60.

A statement that uses the equal sign to show that two expressions have the same value is called an equation. The equation is represented as ax+by=c.

Firstly, we will apply the distributive property to the given equation a×(b+c)=ab+ac, we get

x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60

Now, we will simplify the right-hand side equation by taking LCM, we get

\begin{aligned}\frac{77x+11x+7x+x}{77}&=60\\ \frac{96x}{77}&=60\end

Further, we will multiply both sides with 77, we get

77×(96x/77)=77×60

96x=4620

Then, we will divide both sides with 96, we get

96x/96=4620/96

x=48.125

Hence, the solution of the given equation x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60 is x=48.125.

Learn more about solution of equation from here brainly.com/question/1477785

#SPJ4

4 0
2 years ago
There are 7 students in a class: 5 boys and 2 girls.
iren [92.7K]
3/7 is the answer for this question
3 0
3 years ago
Each row in the table shows how a picture was enlarged or reduced
Fed [463]

Answer:

1. Tall Dog

2. Small Dog

3. Regular Dog

4. Fat Dog

Step-by-step explanation:

It's simple. Look at the problem ;)

8 0
3 years ago
WILL MARK BRAINLIEST PLEASE HELP!!!!!!!!!!!!!!!!!!
defon

Answer

Step-by-step explanation:

I am not an artist so

8 0
3 years ago
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