Q3. In a hydraulic lift, a 1400 N force is applied to a 0.5 m2 piston. Calculate the minimum surface area of the large piston to
lift 5000 N.
1 answer:
Answer:
1.8m^2 approx
Step-by-step explanation:
Given data
P1= 1400N
A1=0.5m^2
P2=5000 N
A2=??
Let us apply the formula to calculate the Area A2
P1/A1= P2/A2
substitute
1400/0.5= 5000/A2
cross multiply
1400*A2= 5000*0.5
1400*A2= 2500
A2= 2500/1400
A2= 1.78
Hence the Area is 1.8m^2 approx
You might be interested in
Answer:
are those 3 different question of just one?
Step-by-step explanation:
Answer: did you ever get the answer ?
Step-by-step explanation:
Answer:
y=5x−17
Step-by-step explanation:
Answer: 24.5
Step-by-step explanation: 1cm/9.8 mi
2.5cm/? 2.5 *9.8= 24.5