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3 years ago

What is the equation of the line that passes through (−3,5) and has a slope of −2?

Mathematics

1 answer:

Tatiana [17]3 years ago

5 0

Answer:

y-5=-2(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

m=-2

y-5=-2(x-(-3))

y-5=-2(x+3)

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Fraction has a fraction in the<br> numerator, denominator, or both

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A fraction is numerator over denominator, most of the time whole numbers

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3 years ago

Which value of x satisfies the equation sin40=cosx

svp [43]

Answer:

Try to use your calculator and just substitute values

Step-by-step explanation:

6 0

3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

How do you find degree measures? How would you solve this question?

MrRa [10]

A. a=145 b=35 c=145 d=145 e=35 f=145 g=35

b. These are the pairs of vertical angles: a & c, b & 35, d & f, e & g.

Hope this was helpful.

8 0

3 years ago

Factor completly: x^2-2x-24

melisa1 [442]

<span>x^2-2x-24 = (x - 6)(x + 4)

cause
</span>(x - 6)(x + 4)
= x^2 - 6x + 4x - 24
= x^2 - 2x - 24

answer
(x - 6)(x + 4)

hope it helps

4 0

3 years ago

Read 2 more answers