Answer:
A.) 0.0129 = k
B.) 2024
Step-by-step explanation:
A.)
267,000 = 250,300e^k5
267,000/250,300 = e^k5
1.0667 = e^k5
ln(1.0667) = lne^k5
ln(1.0667) = 5k
ln(1.0667)/5 = k
0.0129 = k
B.)
300,000 = 250,300^0.0129t
300,000/250,300 = e^0.0129t
1.1986 = e^0.0129t
ln(1.1986) = lne^0.0129t
ln(1.1986) = 0.0129t
ln(1.1986)/0.0129 = t
14.03 = t
so the year would be: 2024
20 is the tenth digit in the quotient
Hello,
(t*s)(x)=t(x)*s(x)=(4x²-x+3)*(x-7)
Answer D
Answer:
The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile
This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.




The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.