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melamori03 [73]
3 years ago
15

What would a biologist see if she examined a small piece of a leaf from a plant and a small piece of a root from the same plant

through a microscope?
Both the leaf and the root would be made up of cells.
O The leaf would be made up of cells, but the root would not be made up of cells.
o The root would be made up of cells, but the leaf would not be made up of cells. Ok
o Neither the root nor the leaf would be made up of cells because plants are not made of cells
up
Chemistry
2 answers:
zubka84 [21]3 years ago
6 0

Answer:

both are made out of cells

Explanation:

both are parts of a plant, plants are liveing things, all liveing things are made of cells.

strojnjashka [21]3 years ago
5 0

Explanation:

What would a biologist see if she examined a small piece of a leaf from a plant and a small piece of a root from the same plant through a microscope? Both the leaf and the root would be made up of cells. The leaf would be made up of cells, but the root would not be made up of cells.

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What mass of NH3 (in grams) must be used to produce 5.65 tons of HNO3 by the Ostwald process, assuming an 80.0 percent yield in
butalik [34]

Answer:

The answer to the question is

The mass of NH3 (in grams) that must be used to produce 5.65 tons of HNO3 by the Ostwald process, assuming an 80.0 percent yield in each step in scientific notation is 3.46 × 10⁶ grams.

Explanation:

The reaction for the Ostwald process is given by

4NH₃ + 5O₂  → 4NO + 6H₂O

2NO + O₂  ↔ 2NO₂

3NO₂ (g) + H₂O (l) → 2HNO₃ + NO

From the reactions of the Ostwald process, 4 moles of NH₃ are required to produce 2 moles of HNO₃

Therefore One mole of HNO₃ requires two moles of NH₃  for production at 100 % theoretical yield

Molar mass of NH₃  =  17.031 g/mol

Molar mass of HNO₃  = 63.01 g/mol

5.65 tons = 5.65 × 2000 lb/ton × 453.6 g/lb = 5125680 g

Number of moles of HNO₃ in 5125680 g sample of HNO₃

= (5125680 g)÷(63.01 g/mol) = 81347.09 moles of HNO₃

However the yield = 80.0%  that is \frac{Actual Yield}{Theoretical Yield} 100 = 80 %

Therefore 80 % Theoretical yield = 81347.09 moles of HNO₃

Theoretical yield = 81347.09 moles ÷ 0.8  = 101683.86 moles

Then 101683.86 moles of HNO₃ will require 2 × 101683.86 moles or 203367.72 moles of NH₃

Mass of 203367.72 moles of NH₃  is given by

mass = number of moles × molar mass = 203367.72 moles ×  17.031 g/mol = 3463555.63 grams

Mass of NH₃ required = 3463555.63 grams = 3.46 × 10⁶ grams  in scientific notation.

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Explanation:

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Explanation:

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3 years ago
Limestone (CaCO₃) is used to remove acidic pollutants from smokestack flue gases. It is heated to form lime (CaO), which reacts
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To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

Equation

CaCO₃ --->CaO + CO2

2 CaO +2 SO2 ----> 2 CaS + 3O2

overall reaction

2 CaCO₃ +2 SO2 ---> 2 CaS + 3O2 + 2CO2

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To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

<h3>Where Is Limestone Found?</h3>

Numerous locations that produce limestone have been recognized by geologists throughout the world. Between 30o N and 30o S latitude, the most of them are in shallow waters. The Caribbean Sea, Indian Ocean, Persian Gulf, and the Gulf of Mexico are the most well-known shallow water locations.

learn more about limestone here

brainly.com/question/15148363

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