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Ilia_Sergeevich [38]
2 years ago
14

Limestone (CaCO₃) is used to remove acidic pollutants from smokestack flue gases. It is heated to form lime (CaO), which reacts

with sulfur dioxide to form calcium sulfite. Assuming a 70.% yield in the overall reaction, what mass of limestone is required to remove all the sulfur dioxide formed by the combustion of 8.5X10⁴ kg of coal that is 0.33 mass % sulfur?
Chemistry
1 answer:
Alex2 years ago
5 0

To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

Equation

CaCO₃ --->CaO + CO2

2 CaO +2 SO2 ----> 2 CaS + 3O2

overall reaction

2 CaCO₃ +2 SO2 ---> 2 CaS + 3O2 + 2CO2

m(S)=8,5 x 10^{4}*0.0033=280.5 kg

n(SO2)= m/Ar(S) = 8,75 x 10^{3}mol

n(CaCO3 needed) = n(SO2) / percent yield

n(CaCO3 needed) = 8.75 x 10^{3}mol / 0.7

​n(CaCO3 needed)= 1.25 x 10 ^4 mol

m(CaCO3 needed) = n x Mr = 1250.62kg

To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

<h3>Where Is Limestone Found?</h3>

Numerous locations that produce limestone have been recognized by geologists throughout the world. Between 30o N and 30o S latitude, the most of them are in shallow waters. The Caribbean Sea, Indian Ocean, Persian Gulf, and the Gulf of Mexico are the most well-known shallow water locations.

learn more about limestone here

brainly.com/question/15148363

#SPJ4

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4 0
3 years ago
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Calculate the mass of CaCl2•2H2O required to make 100.0 mL of a 0.100 M solution. Each of the calculations below will take you t
Zolol [24]

Answer:

The mass is 1.4701 grams and the moles is 0.01.

Explanation:

Based on the given question, the volume of the solution is 100 ml or 0.1 L and the molarity of the solution is 0.100 M. The moles of the solute (in the given case calcium chloride dihydride (CaCl2. H2O) can be determined by using the formula,  

Molarity = moles of solute/volume of solution in liters

Now putting the values we get,  

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

The mass of CaCl2.2H2O can be determined by using the formula,  

Moles = mass/molar mass

The molar mass of CaCl2.2H2O is 147.01 gram per mole. Now putting the values we get,  

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

4 0
3 years ago
What mass of HgO is required to produce 0.692 mol of O2?<br><br>2HgO(s) -&gt; 2Hg(l) + O2(g)
Vika [28.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO  → 2 Hg + O_{2}

where,

HgO represents mercuric oxide

Hg represents mercury

O_{2} represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

molar mass of oxygen (O) =16 grams

HgO = 200 +16 = 216 grams

We know;

       2×216 grams of HgO   →  1 mole of oxygen molecule

             ?                              →  0.692 moles of oxygen molecule

       

          = \frac{2*216*0.692}{1}

      = 298.944 grams of HgO

<u><em>Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule </em></u>

<u />

7 0
3 years ago
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