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kvv77 [185]
3 years ago
6

Alguém poderia me ajudar?

Chemistry
1 answer:
notsponge [240]3 years ago
8 0

Answer: Sorry I can't read it

:(

Explanation:

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How to find oxidation state of a compound?
Hoochie [10]
The oxidation number<span> of a Group 2 element in a </span>compound<span> is +2. The </span>oxidation number<span> of a Group 17 element in a binary </span>compound<span> is -1. The sum of the </span>oxidation numbers<span> of all of the atoms in a neutral </span>compound<span> is 0. The sum of the </span>oxidation numbers<span> in a polyatomic ion is equal to the charge of the ion.</span>
6 0
4 years ago
What fixes nitrogen in the atmosphere
Blababa [14]
<h2>Nitrogen fixation </h2>

Explanation:

It is the process of converting free nitrogen into nitrogenous compounds .

Let us study about it :

In nature there are certain plants called as leguminous plants .These plants have nitrogen fixing bacteria called as rhizobium  in their root nodules .

This bacteria can convert free atmospheric nitrogen into ammonia .

Then this ammonia with the help of bacteria nitrosomonas and nitrobacter gets converted into  nitrites and nitrates .

Then these nitrites and  nitrates with the help of bacteria like pseudomonas gets converted back into free nitrogen ,

This cycle helps in enriching the soil and to maintain nitrogen percent constant in atmosphere ,

The biogeochemical cycle : for nitrogen is attached below  

5 0
3 years ago
What is the molarity of a solution that contains 2.634 mol KCI in 25.2 L solution?O a. 0.105O b. 0.00141O c. 7.73O d. 105
Vikentia [17]

Explanation:

To solve this question, we need to use the following formula:

M = n/V

So:

M = ??

n = 2.634 mol

V = 25.2 L

M = 2.634/25.2

M = 0.105 mol/L

Answer: a. 0.105

4 0
1 year ago
Gold and helium are examples of a(n)
kogti [31]
I guess examples of solid and gas???? You have to be more descriptive.....
4 0
3 years ago
What is the overall process of balancing an equation?
monitta

Answer:

You need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal. :)

3 0
3 years ago
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