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krek1111 [17]
3 years ago
15

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a

sample of sulfur hexafluoride produced 4.44 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produced 4.44 g of fluorine and 1.88 g of sulfur. Calculate the mass of fluorine per gram of sulfur for the sample of sulfur hexafluoride.
Chemistry
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

See Explanation

Explanation:

For SF6;

Since;

1.25 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55

For SF4;

Since;

1.88 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/ 1.88  = 2.36

Hence;

Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4

=

3.55/2.36 = 1.5

Hence the law of multiple proportion is obeyed here.

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Explanation:

E^0_(Cr^{3+}/Cr)=-0.74V[/tex]

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The element  with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

Here Cr undergoes oxidation by loss of electrons, thus act as anode. copper undergoes reduction by gain of electrons and thus act as cathode.

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3 years ago
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How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper
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Hope you could understand.

If you have any query, feel free to ask.

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