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krek1111 [17]
3 years ago
15

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a

sample of sulfur hexafluoride produced 4.44 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produced 4.44 g of fluorine and 1.88 g of sulfur. Calculate the mass of fluorine per gram of sulfur for the sample of sulfur hexafluoride.
Chemistry
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

See Explanation

Explanation:

For SF6;

Since;

1.25 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55

For SF4;

Since;

1.88 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/ 1.88  = 2.36

Hence;

Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4

=

3.55/2.36 = 1.5

Hence the law of multiple proportion is obeyed here.

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Answer:

m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

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Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

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Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3}  *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

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A container with a fixed volume, filled with hydrogen gas at -104°C and 71.8 K PA is heated until the pressure reaches 225.9 K P
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Answer:

The correct answer is 532 K

Explanation:

The Gay-Lussac law describes the behavior of a gas at constant volume, by changing the pressure or temperature. When is heated, the change in pressure of the gas is directly proportional to it absolute temperature (in Kelvin or K).

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If the pressure increases until reaching 225.9 kPa (P2), we can calculate the final temperature of the gas (T2) by using the Gay-Lussac derived expression:

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