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krek1111 [17]
3 years ago
15

Sulfur and fluorine form several different compounds including sulfur hexafluoride and sulfur tetrafluoride. Decomposition of a

sample of sulfur hexafluoride produced 4.44 g of fluorine and 1.25 g of sulfur, while decomposition of a sample of sulfur tetrafluoride produced 4.44 g of fluorine and 1.88 g of sulfur. Calculate the mass of fluorine per gram of sulfur for the sample of sulfur hexafluoride.
Chemistry
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

See Explanation

Explanation:

For SF6;

Since;

1.25 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55

For SF4;

Since;

1.88 g of S corresponds to 4.44g of F

1 g of sulphur corresponds to 1 * 4.44/ 1.88  = 2.36

Hence;

Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4

=

3.55/2.36 = 1.5

Hence the law of multiple proportion is obeyed here.

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Answer:

2.02 times

Explanation:

According to<em> Graham's law</em>, the rate of effusion of two gases can be expresed as:

\frac{Rate_{1}}{Rate_{2}} =\sqrt{\frac{M_{2}}{M_{1}} }

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In this problem, the subscript 1 refers to O₂ gas (32 g/mol), and the subscript 2 refers to Xe gas (131.293 g/mol).

Putting the data in the equation gives us:

\frac{RateO_{2}}{RateXe}=\sqrt{\frac{131.293}{32} }  =2.02

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