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2 years ago

Based on this reaction, how many moles of H2 can be obtained starting with 3 mol CH4?

Chemistry

1 answer:

sleet_krkn [62]2 years ago

5 0

Answer:

9 moles of H₂ are produced

Explanation:

Note: The question is incomplete. the complete question and the given image is found below:

The diagram represents a high-temperature reaction between CH4 and H2O. Based on this reaction, how many moles of H2 can be obtained starting with 3 mol CH4?

From the attachment, the equation of the reaction can be written as:

2CH₄ + 2H₂O ----> 2CO + 6H₂

From the equation the reaction shown above, 2 moles of methane, CH₄ reacts with 2 moles of gaseous water or steam, H₂O (since the reaction occurs at a high temperature) to produce six moles of hydrogen gas, H₂.

Therefore, starting with 3 moles of CH₄ and assuming the number of H₂O are equal to or greater than three moles (since the mole ratio of CH₄ to H₂O is 1 : 1 according to the equation of the reaction), number of moles of H₂ that will be produced = 3 * 6/2 moles of H₂

number of moles of H₂ produced = 9 moles

Therefore, 9 moles of H₂ are produced

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Convert mass to moles for both reactants. (Round to 2 significant figures.)

shepuryov [24]

Mass = mr x moles
Mr of CuCl2 = ( 63.5) + ( 35.5 x 2) = 134.5
2.5 = 134.5 x moles
2.5 / 134.5 = moles
Moles = 0.019 (2DP)

0.25g of Al
Mr of Al = 27
0.25 = 27 x moles
0.25/ 27 = 0.0093 moles (2sf)

Hope this helps :)

6 0

3 years ago

Read 2 more answers

I need Helpppp with my chemistry while we are out of school. I don't have a good teacher and he's not helping since it's his las

9966 [12]

Answer:

im not sure but I hope this helps

Explanation:

I believe the equivalents is just the moles reactant/moles limiting reactant

water has a denisty of 1 g/mL. 1 L is 1000 ml so there are 1000g/L.

the molar mass of water is 18g/mol if you use the Liters in the equation above you can find the number of grams present. divide this number you found by 18 to find the moles.

now take the amount of the other reactant given and divide it by its own molar mass. this will give you the number of moles of that reactant.

divide the moles of water by the moles of the reactant and that is the equivalent.

to find the normality you take this number and divide it by the number of liters.

5 0

3 years ago

Cocaine selectively blocks na+ (sodium) channels, which is the mechanism that leads to

anzhelika [568]

Cocaine selectively blocks sodium channels which is the mechanism that leads to local anesthetic effects.
Voltage gated sodium channels play very important roles in the body as they are responsible for action initiation and propagation in excitable cells, such as nerves, muscles and neuroendocrine cells. Like other sodium ion channels blockers such as lidocaine, Cocaine selectively blocks sodium ion channels which denies entry of sodium ions in the cell, thus leading to local anesthetic effects.

5 0

3 years ago

I need help with this

marshall27 [118]

What is it you need help on? there is nothing here????

ANSWER:

7 0

2 years ago

Read 2 more answers

What is the percent ionization of a 1.8 M HC2H3O2 solution (Ka = 1.8 10-5 ) at 25°C?

xz_007 [3.2K]

Answer:

B) 0.32 %

Explanation:

Given that:

$K_{a}=1.8\times 10^{-5}$

Concentration = 1.8 M

Considering the ICE table for the dissociation of acid as:-

$\begin{matrix}&CH_3COOH&\rightleftharpoons &CH_3COOH&+&H^+\\ At\ time, t = 0 &1.8&&0&&0\\At\ time, t=t_{eq}&-x&&+x&&+x\\ ----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:-&1.8-x&&x&&x\end{matrix}$

The expression for dissociation constant of acid is:

$K_{a}=\frac {\left [ H^{+} \right ]\left [ {CH_3COO}^- \right ]}{[CH_3COOH]}$

$1.8\times 10^{-5}=\frac{x^2}{1.8-x}$

$1.8\left(1.8-x\right)=100000x^2$

Solving for x, we get:

Percentage ionization = $\frac{0.00568}{1.8}\times 100=0.32 \%$

<u>Option B is correct.</u>

8 0

3 years ago