Question

Molar mass of KAl(SO4)^2·12H2O

Answer 1

The molar mass is 477.09 g/mol.

To calculate the molar mass, let’s rewrite the formula as KAlS₂O₈H₂₄O₁₂.Then we can write:

   1 K  =   1 × 39.10  u =   39.10  u

   1 Al =   1 × 26.98 u =  29.68 u

  2 S  =  2 × 32.06 u =  64.12  u

  8 O =  8 × 16.00 u = 128.00 u

24 H = 24 × 1.008 u = 24.192 u

12 O = 12 × 16.00 u = 192.00  u

                  TOTAL = 477.09 u

The molar mass is 477.09 g/mol.

Answer 2

Answer: The molar mass of $KAl(SO_4)_2.12H_2O$ is 474.23 g/mol

Explanation:

Molar mass is defined as the sum of the mass of all the atoms each multiplied its atomic masses that are present in the molecular formula of a compound. It is expressed in g/mol.

We know that:

Molar mass of potassium atom = 39.09 g/mol

Molar mass of aluminium atom = 26.98 g/mol

Molar mass of sulfur atom = 32.06 g/mol

Molar mass of oxygen atom = 15.99 g/mol

Molar mass of hydrogen atom = 1.01 g/mol

The chemical formula of the given compound is $KAl(SO_4)_2.12H_2O$

Molar mass of $KAl(SO_4)_2.12H_2O=[(1\times 39.09)+(1\times 26.98)+2(32.06+(4\times 15.99))+12((2\times 1.01)+15.99)]=474.23g/mol$

Hence, the molar mass of $KAl(SO_4)_2.12H_2O$ is 474.23 g/mol