To find Tim's overall score, first we must find the sum of his scores from quizzes, notes, and tests.
Hence, we have
quizzes = (5 + 2 + 9) = 16/3
notes = (3 + 9 + 5)/3 = 17/3
tests = (9 + 5 + 9)/3 = 23/3
Now, we must consider the percentage that these tests contribute to his overall score. So we have the following:
quizzes = 0.5(16)/3 = 8/3
notes = 0.2(17)/3 = 3.4/3
tests = 0.3(23)/3 = 6.9/3
We now add these to find the overall score which is 8 /3+ 3.4/3 + 6.9/3 = 18.3/3 = 6.1.
Thus, Tim's overall score is 6.1.
Answer: 6.1
Answer:
a
Step-by-step explanation:
Answer:
-9
Step-by-step explanation:
the number 60+3 can be als0 written as 63
Answer:
1050 g < weight ≤ 1150 g
Step-by-step explanation:
Let w represent the weight of the package in grams. The the number of 100-gram increments after the first 250 grams is given by ...
⌈(w-250)/100⌉ . . . . . . . where ⌈ ⌉ signifies the <em>ceiling</em> function
and the charges for a package exceeding 250 grams will be ...
0.65 + 0.10⌈(w -250)/100⌉ = 1.55
0.10⌈(w -250)/100⌉ = 0.90 . . . . . . . . subtract 0.65
⌈(w -250)/100⌉ = 9 . . . . . . . . . . . . . . . divide by 0.10
8 < (w-250)/100 ≤ 9 . . . . . . . . . . . . . . meaning of ceiling function
800 < w -250 ≤ 900 . . . . . . . . . . . . . multiply by 100
1050 < w ≤ 1150 . . . . . . . . . . . . . . . . . add 250
The weight in grams could be greater than 1050 and at most 1150 for a charge of $1.55.