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Deffense [45]
3 years ago
11

Please help.............:)

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

113

Step-by-step explanation:

Multiply

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The cost to print digital photos at a local store is
snow_tiger [21]
<h2>The cost is same for both the options if we purchase 27 photos</h2>

Step-by-step explanation:

   Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as C_{1}(x)=0.25x.

   Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as C_{2}(x)=2.70+0.15x.

   Let us assume both costs are the same if we purchase n photos.

So, C_{1}(n)=C_{2}(n)

0.25n=2.70+0.15n

0.10n=2.70

n=27

∴ On purchasing 27 photos, cost for both the options is the same.

5 0
3 years ago
Read 2 more answers
Help plz !! I will give you points or anything !!
pashok25 [27]

Answer:

Answer C is correct

Step-by-step explanation:

-200(3/4) = -600/4 = -150 ft

3 0
2 years ago
Explain how to correctly find the missing side
kotegsom [21]

Pythagorean Theorem

a² + b² = c²

c = 13

a = 4

(Missing side) = b

4² + b² = 13²

16 + b² = 169

16 - 16

169 - 16 = 153

Square Root of 153 = 12.369

b = 12.369

The missing side is 12.369 (rounded to 12 as a whole number)

6 0
2 years ago
Read 2 more answers
g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od
cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

6 0
3 years ago
Marcos charges $6 an hour to work in his neighborhoods gardens. Complete the graph to show proportional relationship of the amou
NISA [10]

Answer:

120

Step-by-step explanation:

6 0
3 years ago
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