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Julli [10]
3 years ago
15

Two electrically opposite charges are separated by a fixed distance. Which action will provide the greatest increase in the forc

e of attraction between the charges?
Physics
1 answer:
Alex73 [517]3 years ago
6 0

Explanation:

The electric force between charges is given by the formula as follows :

F=\dfrac{kq_1q_2}{r^2}

k is electrostatic constant

r is distance between charges

Here, charges are equal and opposite. So,

F=\dfrac{kq^2}{r^2}

It is clear the force is inversely proportional to the distance between charges and directly proportional to the product of charges. So, greatest force will be providing by :

  • Increasing the magnitude of charges
  • Decreasing the distance between charges.
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What are ways to improve the design of this experiment? Check all that apply
Serhud [2]

Answer:

B,D,E

Explanation:

I got you

B. Experiment with a wider range of materials.

D.Use a laboratory galvanometer to make precise measurements.

E. Test the strength of the electromagnet by varying the number of wire coils.

3 0
3 years ago
if you are in Birmingham AL, and you want to use your cell phone to talk to your cousin in Houston, TX, what must occur in order
lesantik [10]

Answer:

For communication to be communicated between you and your cousin who is in Houston,Texas, when a call is made by you, a request is made to the specific phone, and the telephone tower will get the request from the mobile phone. Then a signal is sent via a transmitter underground, by this the satellite communicates with the local receiver in Houston, that is linked to the local tower over there, the tower would request for your cousin's number and connects the two of you, once a link is set.

Explanation:

From the example stated, what is required for such for a far distance, is a communication satellite link.

When a call is made by you, the a connection request is sent to the specified phone.The telephone tower receives the request from The mobile phone. The local tower(Birmingham,Al) is linked to a ground transmitter by the means of a Fiber optical cable.

A signal is sent to satellite via the ground transmitter.The satellite then set's off the local receiver in (Houston,Texas) which on it's end is connected to the local tower there. This tower then ask for your cousin's mobile for a call that will be incoming, a link is set, once he/she receives the call, from there a conversation can be done.

3 0
4 years ago
What 2 things do you need to make sound? help ASAP
inessss [21]

Answer:

- A vibrating object

- a medium to travel

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

8 0
3 years ago
An old-fashioned LP record rotates at 33 1/3 RPM
Ksenya-84 [330]

Answer:

Part a) \frac{5}{9}\ \frac{rev}{sec}

Part b) \frac{9}{5}\ \frac{sec}{rev}

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

33\frac{1}{3}\ \frac{rev}{min}

Convert mixed number to an improper fraction

33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}

Remember that

1\ min=60\ sec

Convert rev/min to rev/sec

\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}

Simplify

\frac{5}{9}\ \frac{rev}{sec}

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

\frac{9}{5}\ \frac{sec}{rev}

4 0
3 years ago
How do you compare the energies of the different parts of the electromagnetic spectrum?
faltersainse [42]

The different types of radiation in electromagnetic spectrum are compared by the amount of energy found in the photons.

Radio waves have photons with low energies, microwave photons have a little more energy than radio-waves. Infrared photons still have more energy, then comes visible, ultraviolet, x-rays and the most energetic of all, gamma rays.

The energy associated with electromagnetic radiation is proportional to frequency and inversely proportional to wavelength. So, electromagnetic waves with shorter wavelengths have more energy.

On one end of the electromagnetic spectrum are radio waves, which have wavelengths billions of times longer than those of visible light. On the other end of the spectrum are gamma rays with wavelengths billions of times smaller than those of visible light.

To know more about electromagnetic spectrum:

brainly.com/question/27839167

#SPJ4

5 0
1 year ago
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