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Nataliya [291]
3 years ago
14

If do 50 J of Work in 20 seconds, what is my Power ?

Physics
1 answer:
pochemuha3 years ago
8 0

Answer: P= W/t so P=50/20 =2.5 W

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G a small metal sphere, carrying a net charge is held stationary. what is the speed are 0.4 m apart
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Answer:

The final speed of small metal sphere is 12.6 m/s.

Explanation:

Given that,

Distance = 0.4 m

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the final speed of small metal sphere

Using conservation of energy

\dfrac{1}{2}mv_{1}^2+\dfrac{kq_{1}q_{2}}{r_{1}}=\dfrac{1}{2}mv_{2}^2+\dfrac{kq_{1}q_{2}}{r_{2}}

\dfrac{1}{2}m(v_{1}^2-v_{2}^2)=kq_{1}q_{2}(\dfrac{1}{r_{2}}-\dfrac{1}{r_{1}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{2}^2)=9\times10^{9}\times(-2)\times10^{-6}\times(-8)\times10^{-6}(\dfrac{1}{0.4}-\dfrac{1}{0.8})

400-v_{2}^2=240

-v_{2}^2=240-400

v_{2}=\sqrt{160}\ m/s

v_{2}=12.6\ m/s

Hence, The final speed of small metal sphere is 12.6 m/s.

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3 years ago
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