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nydimaria [60]
3 years ago
5

Evaluate Combination (6,6)

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

6C6

And the general formula for combination is given by:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

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Marizza181 [45]

Answer:

40 degrees : )

4 0
3 years ago
One half X +13 equals nine
NeTakaya
\frac{1}{2}x+13=9
\frac{1}{2}x=9-13
\frac{1}{2}x=-4
x=-4*2
x=-8
Answer: x=-8
5 0
4 years ago
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The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

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4 0
3 years ago
Find f(-7) when f(x)=- 29/x-4
vladimir1956 [14]

Answer:

f(-)=29/11

Step-by-step explanation:

Even though you don't want an explanation, I'll just tell you the basics lol.

So what you have to do, is plug in -7 for the x's.

it should look something like the equation below.

f\left(-7\right)=\frac{-29}{-7-4}

After that all you need to is just to subtract :)

f\left(-7\right)=\frac{-29}{-11}

Then after that all you need to do is just let the negatives cancel out each other so you should get:

f\left(-7\right)=\frac{29}{11}

Hope this helps!

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1st 159.967 2nd 7.52711×10^-14 3rd 1.59078×10^13
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