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siniylev [52]
3 years ago
8

Each number in the sequence is 8 less than the previous number which list of number can be described by the following rule

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer: a

Step-by-step explanation:

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(this is 6 grade math) PLEASE HELP<br>​
pochemuha
Answer
11a + 4a= 15a
3x + 6 +7x -4 = 12x
-12m -3 + 4m + 16 = 29m
6k-4+k-2 =4K
3+13-5p-2p =9p

I think these are the answers please don’t get mad if they are not hope I help :)
8 0
3 years ago
Read 2 more answers
A trapezoid has an area of 30m^2. if all of its side lengths are tripled, what will its new area be​
Norma-Jean [14]

Answer:

270

Step-by-step explanation:

Because we do not know what the side lengths are, as long as they multiply to 30m^2, it's fine

For this question, let's just say the base is 5, and the height is 6. If we triple 5, we get 15, and if we triple 6, we get 18. 15*18=270

Now what if, the sides are not 5 and 6. Will the area still be the same? Let's find out.

10*3=30 so we can say for this answer, the base is 3, and the height is 10.

10 tripled is 30, and 3 tripled is 9. 30*9=270

So as we look at these 2 answers. we can conclude that the new area, no matter the side lengths, will be 270

Hope this helpes!

5 0
4 years ago
At one basketball game there were 1207 people. At the next game they were 958 people how many people were at two games?
LenKa [72]
2165 people were at the two basket ball games.
8 0
4 years ago
There is a​ 10% chance of the mean​ oil-change time being at or below the sample mean for which there is an area of 0.10 to the
Zarrin [17]
The probability that a normally distributed data with a mean of μ and a standard deviation of σ is less than a value x is given by:

P(X\ \textless \ x)=P\left(z\ \textless \  \frac{x-\mu}{\sigma} \right)

Given that μ = 16.5 and σ = 0.804984 and that the probability that the <span>mean​ oil-change time being at or below the sample mean for which there is an area of 0.10 to the left under the normal curve, then:

P\left(z\ \textless \  \frac{x-16.5}{0.804984} \right)=0.1\\  \\ \Rightarrow P\left(z\ \textless \  \frac{x-16.5}{0.804984} \right)=P(z\ \textless \ -1.281) \\  \\ \Rightarrow\frac{x-16.5}{0.804984}=-1.281 \\  \\ \Rightarrow x-16.5=-1.281(0.804984)=-1.031 \\  \\ x=-1.031+16.5=15.47</span>
6 0
4 years ago
Find the value of y​
bezimeni [28]

Answer:

the value of y is 27 such a silli question

6 0
4 years ago
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