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3 years ago

Whats the answer is for math btw fidsf

Mathematics

1 answer:

ra1l [238]3 years ago

6 0

Step-by-step explanation:

Since this is a select as many answers that are right, there are obviously many answers that are correct.

First, you get m by itself, so you divide 6 with 300.

So,

6m < 300

___ ___

6 6

m < 50

So the answers are numbers less than 50.

Which are the first four answers:

A, B, C, D

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3 years ago

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3 years ago

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All items produced in a factory are checked for defects. Of the 300 items checked, 3% were found to be defective. How many of th

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3 years ago

I don't understand what the answer is supposed to be, none of my answers match.

jolli1 [7]

The rational expression is the following

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}$

By applying the sandwich rule:

we have

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}$

which gives

$\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}=\frac{(x-1)(2y)}{(2\cdot3xy)(5)}=\frac{(x-1)(2y)}{(3x\cdot2y)(5)}=\frac{x-1}{3x\cdot5}=\frac{x-1}{15x}$

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2 years ago

In the formula A(t)equals=Upper A0A0 Superscript ktkt, A is the amount of radioactive material remaining from an initial amoun

Ivan

Answer:

693 Years

Step-by-step explanation:

Given an initial amount $A_o$ and k (a negative constant) determined by the nature of the material, the amount of radioactive material remaining at a given time t, is determined using he formula:

$A(t)= A_oe^{kt}$

If a certain radioactive isotope decays at a rate of 0.1% annually.

$\frac{1}{2} A_o= A_oe^{-0.001t}\\e^{-0.001t}=\frac{1}{2}\\$Take the natural logarithm of both sides\\-0.001t=ln(0.5)\\t=ln(0.5) \div -0.001\\t=693.15\approx 693 \:years$

The half-life of the isotope is 693 years.

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3 years ago