HELP ASAP!!! Identify the factored form of each polynomial

Mathematics

1 answer:

Elenna [48]3 years ago

7 0

Answer:

9x2 +42x + 24 is (x + 4) (9x + 6)

9x2 + 30x + 24 is (3x + 6) (3x + 4)

9x2 + 58x + 24 is (9x + 4) (3x + 4)

I tried reversing it, instead of doing these - 9x2 + 58x + 24 I did (9x + 4) (3x + 4)

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You are spreading fertilizer on a golf course at the rate of 40 pounds per 10,000 square feet. If the course is 320 acres, how m

Amanda [17]

An acre has 4840 yd², and since a yard is 3 feet, a (yd)² is (3 ft)², or 3² ft² or 9 ft².

how many ft² are there in an acre? well, in 4840 yd² there are 4840 * 9 ft².

this golf course is 320 in area, since there are (4840 * 9) ft² in one acre, then 320 acres will be (320 * 4840 * 9) ft².

how many sections of 10,000 ft² are there? well, (320 * 4840 * 9) / 10000.

every 10000 ft² section is getting 40lbs of fertilizer, so the total amount of fertilizer is [ (320 * 4840 * 9) / 10000 ] * 40.

how many tons is that? well, there are 2000lbs in a ton, thus that'd be
[ [ (320 * 4840 * 9) / 10000 ] * 40 ] / 2000.

3 0

3 years ago

2/3n =10 solve for n

geniusboy [140]

N will equal 15
hope this helps

8 0

4 years ago

Read 2 more answers

In a class of 18 students, 5 are math majors. A group of four students is chosen at random. (Round your answers to four decimal

ss7ja [257]

Answer:

(a) 0.2721

(b) 0.7279

Step-by-step explanation:

(a) If we choose only one student, the probability of being a math major is $\frac{5}{18}$ (because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is $\frac{18}{18} - \frac{5}{18} = \frac{13}{18}$ (we subtract the math majors of the total of students).

But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is $\frac{13}{18}$ and we have to multiply them because it happens all at the same time.

P (no math majors in the group) = $\frac{13}{18} *\frac{13}{18}*\frac{13}{18}*\frac{13}{18} = (\frac{13}{18}) ^4$ = 0.2721

(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).

So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279

(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is $\frac{13}{18}$ . We need two of both, that's $\frac{5}{18}*\frac{5}{18}*\frac{13}{18}*\frac{13}{18}$ . But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient $\binom{4}{2}$ .