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arsen [322]
3 years ago
8

Simplify 6 to the negative 3rd power over 6 to the 5th.

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0
The answer is 6 to the positive 2 power beau see -3 plus 5 equals to positive 2, also the base remains same bemuse they are both 6
Ugo [173]3 years ago
6 0
To simplify \frac{6^{-3}}{6^5}
\frac{6^{-3}}{6^5}

\frac{\frac{1}{6^3}}{6^5}
\frac{1}{6^3}\times\frac{{6^5}}{1} = \frac{1}{36} = \frac{1}{6^2}
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Cathy rolls a number cube that is labeled from 1 to 6.
MatroZZZ [7]

Answer: 2/3

Cathy rolls a number cube that is labeled from 1 to 6.

Total outcomes = {1,2,3,4,5,6}

she rolls an even number or a multiple of 3

Outcomes of an even number = {2,4,6}

Outcomes of multiple of 3 = {3,6}

so favorable outcomes of even number or a multiple of 3 = {2,3,4,6}

Probability ( any event) =number of favorable outcomes divide by total  number of outcomes

probability(even number or a multiple of 3) = \frac{4}{6}=\frac{2}{3}

7 0
3 years ago
A) If a + 5 = 15, then find the value of a​
ozzi

Answer:

The answer is 10

Step-by-step explanation:

a + 5 =15

15-5=10

6 0
3 years ago
Read 2 more answers
Solve the following formula for b<br><br> y=6(5a+3b)<br> what does b equal
Ratling [72]

Answer:

30a + 18b

Step-by-step explanation:

6(5a+3b)

Just multiply the six in both numbers

( 6x5a) + (6x3b)

= 30a +18b

Hope this helps =)

4 0
3 years ago
PLEASE PLEASE HELP ME
mina [271]
The answer is <EKF and <HKI
3 0
3 years ago
Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans
tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

__

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0
2 years ago
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