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arsen [322]
3 years ago
8

Simplify 6 to the negative 3rd power over 6 to the 5th.

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0
The answer is 6 to the positive 2 power beau see -3 plus 5 equals to positive 2, also the base remains same bemuse they are both 6
Ugo [173]3 years ago
6 0
To simplify \frac{6^{-3}}{6^5}
\frac{6^{-3}}{6^5}

\frac{\frac{1}{6^3}}{6^5}
\frac{1}{6^3}\times\frac{{6^5}}{1} = \frac{1}{36} = \frac{1}{6^2}
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find the equation of a line that is perpendicular to line g that contains (P,Q) will give brainlest to whoever answers
Fudgin [204]

Answer:

Consider points (-3,6) and (0,5)

gradient \:  \: m =  \frac{(6 - 5)}{( - 3 - 0)}  \\ m =  -  \frac{1}{3}  \\ for \: perpendicular \: gradient \: m {}^{.}  \\ m {}^{.}  \times m =  - 1 \\  -  \frac{1}{3} m {}^{.}  =  - 1 \\ m {}^{.}  = 3 \\ from \: y = mx + c \\ at \:(0,5) \:  \: 5 = 0 \times 3 + c \\ c = 5 \\ hence \: equation \: is \:  \: y = 3x + 5

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3 years ago
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How many hours are in 188 days
Anettt [7]
24*188=4512

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Please help me with this question!!<br><br> Slope of covalent bond (RED) =
kifflom [539]
Answer: 10

Step by Step Solution:
You have x and y as your axis’s and that as your table with x being time and y being percent bounded. As for that you got (0, 0) and (5, 50).

Then you plug those numbers into the equation to finding slope: m = y2 - y1 / x2 - x1 to have m = 50 - 0 / 5 - 0

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8 0
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A certain number was multiplied by 3. then, this product was divided by 3. Finally, 5 was subtracted from this quotient, resulti
natulia [17]

Answer:

2

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Sin(a+b)*sin(a-b)=cos^2b-cos^2a
garik1379 [7]

Answer:

Step-by-step explanation:

To prove sin(a+b)*sin(a-b)=cos^2b-cos^2a

we simplify the left side  sin(a+b)*sin(a-b) first

sin(a+b) = sin a cos b + cos a sin b

sin(a-b) = sin a cos b - cos a sin b

sin(a+b)*sin(a-b) = (sin a cos b + cos a sin b) x (sin a cos b -cos a sin b)

sin a cos b((sin a cos b + cos a sin b) - cos a sin b (sin a cos b + cos a sin b)

open the bracket

sin a cos b(sin a cos b) + sin a cos b(cos a sin b) -cos a sin b (sin a cos b)+ cos a sin b ( cos a sin b)

sin²a cos²b + sin a cos b cos a sin b - cos a sin b sin a cos b + cos²a sin²b

sin²a cos²b  + 0 + cos²a sin²b

sin²a cos²b + cos²a sin²b

  • sin²a  = 1-cos² a
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(1-cos² a)cos² b - cos² a(1-cos² b)

= cos² b - cos² a cos² b - cos² a +cos² a cos² b

  • choose like terms

cos² b - cos² a - cos² a cos² b + cos² a cos² b = cos² b - cos² a  + 0

cos² b - cos² a

left hand side equals right hand side

5 0
4 years ago
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