Answer:
Total eclipse was
minutes longer than in 2005.
Step-by-step explanation:
It is given in the question that total eclipse in 2003 lasted
minutes and in 2005 it lasted 3/8 of a minute.
We have to calculate how much longer did it last in 2003.
So we have to subtract the duration in 2003 by duration in 2005
Total time taken in 2003- total time taken in 2005





minutes
Answer:
<h2>
45°</h2>
Step-by-step explanation:
they are opposite angles, same value of 45°
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
You would distibute first distribute
6x-10=8
add 10 on both sides
6x=18
Then you divide 6 on both sides to get x by itself so
x=3
Time = Distance / speed
Time = 20 miles / 12mph
Time = 1 and 2/3 hours ( 1 hour and 40 minutes)