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tigry1 [53]
3 years ago
11

M1|L7 1 Decimal Round Round 5.489 to the nearest hundredth. ) Label the endpoints. )

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

5.49

Step-by-step explanation:

5.48<u>9,</u> the number 9 that is underlined is 5 or more so you put that at 0 then it would be 5.48, but since the 8 is also 5 or more and is the hundreths place you round that to 9 giving you 5.49

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What is the value of x and y?
ladessa [460]

Answer:

x=16 and y=9

Step-by-step explanation:

2y+30=3y+21[Diagonals of parallelogram are equal]

30-21=3y-2y

y=9

3y=2x-5[Diagonals of parallelogram are equal]

3×9=2x-5

27=2x-5

2x=27+5

x=32/2=16

5 0
2 years ago
if tom spins the spinner 80 times work out an estimate for the number of times the spinner will land on 3 please help me
NNADVOKAT [17]

Answer:

The estimated number of times the spinner will land on 3 is 20.

Step-by-step explanation:

The complete question is:

A four-sided spinner is provided. If Tom spins the spinner 80 times then work out an estimate for the number of times the spinner will land on 3.

Solution:

Assume that the four-sided spinner is unbiased.

That is all the four outcomes are equally likely to be selected.

The probability that the spinner lands on any of the four numbers is:

P(1) = P (2) = P (3) = P (4) = 0.25

It is provided that Tom spins the spinner <em>n</em> = 80 times.

The spinner can land on any of the four numbers independently.

The random variable <em>X</em>, defined as the number of times the spinner lands on 3, follows a Binomial distribution with parameters <em>n</em> = 80 and <em>p</em> = 0.25.

The expected value of <em>X</em> is:

E(X)=np

        =80\times 0.25\\=20

Thus, the estimated number of times the spinner will land on 3 is 20.

7 0
3 years ago
Help please. I need this in a few minutes
Ghella [55]

Answer:

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
Which is the length of x? 1 7/9 2 1/2 1 1/4 1 3/5
trapecia [35]

Answer:

option D.  x = 1 3/5

Step-by-step explanation:

ratio and proportion

<u> 4 </u> = <u> x </u>

5     2

X multiply:

5x = 4(2)

5x = 8

x = 8 / 5

x = 1 3/5

5 0
3 years ago
Read 2 more answers
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