I believe it’s 8^3 I’m sorry if it’s wrong!!!!
I wish I could help but I’m taking it right now too. I’m struggling lol
Answer:

Step-by-step explanation:
If the extreme ends of a line segment AC are A
and C
.
If a point B(x, y) divides the segment in the ratio of m : n
Then the coordinates of the point B are,
x = 
y = 
If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1
Therefore, coordinates of this point will be,
x = 
= 
= 
= 
y = 
= 
= 
= 
Therefore, coordinates of the point B are
.