It's an example of a molecule
The number of grams of oxygen present in 1.75 moles of calcium carbonate is 84 grams
Explanation
mass = moles x molar mass
molar mass = 16 g/mol
find the number of moles of oxygen in calcium carbonate as below
formula of calcium carbonate is CaCO3
from the formula above have three(3) atoms of oxygen
therefore the moles of 0xygen = 3 x 1.75 =5.25 moles
mass of oxygen is therefore = 5.25 moles x16g/mol = 84 grams of oxygen
Answer:
the volume of sea water is 85866.407 L, necessary to extract 8.0 E4 tons of Mg
Explanation:
- %p/p = 1.3 g Mg / 1000g seawater ) * 100 = 0.13 %
⇒ 8.0 E4 ton Mg * ( 0.00110231 Kg / ton ) = 88.1848 Kg Mg
⇒ 0.13 % = ( 88.1848 Kg Mg / Kg seawater ) * 100
⇒ ( 0.13 / 100 ) = 88.1848 / Kg seawater
⇒ Kg seawater = 88.1848 / 1 E-3
⇒ Kg seawater = 88184.8 Kg
⇒ Vseawater = mass seawater / density seawater
∴ density seawater = 1027 Kg / m³...from literature
⇒ V seawater = 88184.8 Kg / 1027 Kg/m³
⇒ V seawater = 85.866 m³ * ( 1000L / m³ )
⇒ V seawater = 85866.407 L
I have a feeling that #2 is the one.
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