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2 years ago

I need help with this question please help me

Chemistry

1 answer:

bulgar [2K]2 years ago

8 0

8xc take away 8xExplanation:

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What is the name of a compound having the formula Al2O3? (5 points)

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4) Aluminum Oxide

Explanation:

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Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO

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The molarity of a solution is the number of moles of a substance divided by the volume in liters prepared.

$molarity=\frac{n}{V}$ , where n is number of moles and V is the volume in liters.

In order to calculate the mass of solute we need to convert the volume and molarity to moles

$1.421 L solution \times\frac{0.0730 moles}{1 Lsolution}= 1.037 mol NaCO_3$

Now that we have moles we use the relative formula mass of NaCO₃, We have 1 Na atom, 1 C atom and 3 O atoms, thus

$M_r= (1\times 22.99) + (1\times 12.00) + (3\times 16.00)= 82.99g/mol$

$1.037 \times\frac{82.99g}{mol} = 86.1g$

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3 years ago

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What is the hybridization of the central atom in becl2?

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Its hybridization would be sp because Be only has 2 covalent bonds with Cl

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At which temperature will the least amount of time pass before someone detects the odor of a fragrant flower?

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Americans combined drive about 4.0 x 109 kilometers a day and get an average of 20 miles per gallon of gasoline. For each kilogr

Nimfa-mama [501]

Answer:

$303,882.84649 kg\times 3=9.12\times 10^5 kg$ of carbon dioxide gas.

Explanation:

Average distance covered by Americans in a day= $4.0\times 10^9 km$

1 day = 24 × 60 min = 1,440 min

Average distance covered by Americans in a minute= $\frac{4.0\times 10^9 km}{1,440}=2,777,777.78 km$

Average mileage of the car = 20 miles/gal = 32.18 km/gal

1 mile = 1.609 km

20 miles = 20 × 1.609 km = 32.18 km

Volume of gasoline used in minute = $\frac{2,777,777.78 km}{32.18 km/gal}$

$V=86,320.00 gal$

$V=86,320.00\times 3.7854 L$

(1 L = 1000 mL)

$V=86,320.00\times 3.7854 \times 1000 mL=326,755,748.91 mL$

Mass of 86,320.00 gallons of gasoline = m

Density of the gasoline = d = $0.93 g/cm^3=0.93 g/mL$

$1 mL= 1 cm^3$

$m=d\times V=0.93 g/mL\times 326,755,748.91 mL$

$m=303,882,846.49 g=303,882.84649 kg$

1 kilogram of gasoline gives 3 kg of carbon dioxde gas .

Then 303,882.84649 kg of gasoline will give :

$303,882.84649 kg\times 3=9.12\times 10^5 kg$ of carbon dioxide gas.

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2 years ago