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nexus9112 [7]
3 years ago
8

If the perimeter of is square sarden is 84 feet what is the area of the garden

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0
Because it’s a square garden each side is the same meaning 84/4 will give you the length of each side, in this case 21. to work out the area it is length x width so 21 x 21 is 441!
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This can be solved by finding their point of intersection on the graph, which is at point (1,3).
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If anyone’s good with geometry, help me out please. I would really appreciate it.
lakkis [162]

Answer: X=2, PR=40

Step-by-step explanation:

given that the two triangles are equal/congruent

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solve for x

10x+5=25

10x=20

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33=7y-2

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Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1
Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

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Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

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An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
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Answer:

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Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

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(e^{Kt}P(t))'=3,000,000Ke^{Kt}

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P(t)=3,000,000+Ce^{-Kt}

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and P(50) = 1,500,000

so

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