Answer:
I believe that is correct. You're smart. :) stay safe!
Breads and cheese's
Hope this helps:)
-Warning2
Answer:
Type A blood or Type B blood
Explanation:
O is a recessive trait so both allels would have to be O for it to be O type blood, and none of the punett squares contain 2 O's
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
This is the <span>Fayum </span>depression. Here, fossil evidence of a primate ancestor<span> was found predating the divergence between </span>hominoids<span> (apes and </span>humans<span>) and </span>cercopithecids<span> (Old World monkeys). The fossil of a single species </span><span>lived around 30 million years ago in modern-day Egypt and resembled the current New-World monkeys. </span>
