Answer:
Step-by-step explanation:
9
1. ∠ACB ≅∠ECD ; vertical angles are congruent (A)
2. C is midpoint of AE ; given
3. AC ≅CE; midpoint divides the line segment in 2 congruent segments (S)
4.AB║DE; given
5. ∠A≅∠E; alternate interior angles are congruent (A)
6. ΔABC≅ΔEDC; Angle-Side-Angle congruency theorem
10
1. YX≅ZX; given (S)
2. WX bisects ∠YXZ; given
3. ∠YXW≅∠ZXW; definition of angle bisectors (A)
4. WX ≅WX; reflexive propriety(S)
5. ΔWYX≅ΔWZX; Side-Angle-Side theorem
Answer:(3/5 times 5/6 = 1/2)
Step-by-step explanation:
Answer:
Part A = the middle one
Part B = 4 days
Step-by-step explanation:
1,300 / 4 = 325
325 x 4 = 1,300
Answer: 20 mph
Explanation:
Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:
(1)
During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:
(2)
So we have two equations with two unknown variables. From (1), we get

Substituting into eq.(2)

So, the speed of the wind was 20 mph.