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2 years ago

Find the solution of this system of equations.

Mathematics

1 answer:

german2 years ago

8 0

16+ 44 so I =60 hdndmoaoaoajebdbvdjjssksk

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The diagnoal of a rectangle is 25 inches and the width is 15 inches what is the length

Grace [21]

Answer:

20 inches

Step-by-step explanation:

3 0

3 years ago

Write the equation for the line that goes through point (12, 15) with slope = −2.

pogonyaev

Answer:

y= -2x +39

Step-by-step explanation:

y= mx+b

m is the slope which is given -2

since we don't know b we can solve the rest using the formula y-y1{ m(x-X1(

y - 15 = -2(x-12)

simplify

y-15= -2x +24

y= -2x + 39

7 0

2 years ago

Read 2 more answers

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.

solniwko [45]

For this case we have to:

Let $u = x + 1$

So:

$u ^ 2-4u + 2 = 0$

We have the solution will be given by:

$u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = 1\\b = -4\\c = 2$

Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

Answer:

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

3 0

2 years ago

Read 2 more answers

Round 12.03994 to 3 decimal place

Misha Larkins [42]

$12.03994\to\boxed{12.04}$

8 0

2 years ago

Angelica did an experiment where she measured the temperature outside her house each day for two weeks. She found that on the fi

USPshnik [31]

I think it would be a

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3 years ago