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2 years ago

Write the eguation of the line through (-8,-6) with slope = -5

Mathematics

2 answers:

Marta_Voda [28]2 years ago

7 0

Answer:

Y=-5x-46.

Step-by-step explanation:

-5 is the slope, so Y=-5x+b. If you plug in (-8,-6), you get -6=40+b, so b has to be -46 for that to be true, I think.

Lubov Fominskaja [6]2 years ago

3 0

Answer:

Y=-5x-46

Step-by-step explanation:

Hope this helped!

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Answer:

Add all the values up and divide by 7 ( as there are 7 values in the data set)

Step-by-step explanation:

1.9 + 10 + 11 + 16 + 12 + 12 + 14 = 76.9

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3 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

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3 years ago

What is3/4 - 1/2 and what is 7/8-2/3

Mariulka [41]

3/4 - 1/2 = 3/4 - 2/4 = 1/4

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3 years ago