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Marianna [84]
3 years ago
10

Sally says it is possible to draw a triangle with these side length

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Step-by-step explanation:

The longest side of a triangle cannot be longer than the sum of the two shorter sides. So if the 5cm and 12cm sides are the shorter sides, the third one cannot be longer than the 17cm. ... So 12cm is not longer than 5cm plus the length of the third side, and therefore the missing side cannot be shorter than 7cm.

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Write 0.0166 correct to two significant figures.
s2008m [1.1K]

Answer:

0.016

Step-by-step explanation:

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3 years ago
One number is 10 times as large as another, and their difference is 81. Find the numbers.
marysya [2.9K]

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90

Step-by-step explanation:

10x - x = 81

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Determine if the two triangles are congruent. If so, select the appropriate congruence postulate. If not, select the reason why.
morpeh [17]

Answer:

Asa

Step-by-step explanation:

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4 0
2 years ago
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Radda [10]

its B. 50°

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Half of triangle Have 90°

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5 0
2 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
3 years ago
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