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Ksju [112]
3 years ago
6

What is the product (-2d^2+s)(5d^2-6s)

Mathematics
2 answers:
taurus [48]3 years ago
7 0
<span><span><span> The answer is −10</span><span>d4</span></span>+<span><span>17<span>d2</span></span>s</span></span><span><span>−6</span><span>s<span>2</span></span></span>
netineya [11]3 years ago
7 0

Answer

Find out the product of the  (-2d²+s)(5d²-6s) .

To prove

As given the expression in the question is

= (-2d²+s)(5d²-6s)

= -2d^{2}\times 5d^{2} + s\times 5d^{2} - 2d^{2}\times -6s + s\times -6s

Now using the exponent property

x^{a}\times x^{b} = x^{a+b}

Simplify the above

= -10d^{2 +2} + 5sd^{2} +12sd^{2} -6s^{2}

= -10d^{4} + 5sd^{2} +12sd^{2} -6s^{2}

= -10d^{4} + 17sd^{2} -6s^{2}

Therefore the product of (-2d²+s)(5d²-6s) is -10d^{4} + 17sd^{2} -6s^{2}





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