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Alex_Xolod [135]
3 years ago
10

Find the indicated limit, if it exists.(7 points)

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

7

Step-by-step explanation:

The left hand limit is when we approach zero from left. We use the function on this domain in finding the limit.

\lim_{x \to 0^-} f(x)=7-x^2

\lim_{x \to 0^-} f(x)=7-(0)^2=7

The right hand limit is

\lim_{x \to 0^+} f(x)=10x+7

\lim_{x \to 0^+} f(x)=10(0)+7=7

Since the left hand limit equals the right hand limit;

\lim_{x \to 0} f(x)=7

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What were the lengths of the legs of a right triangle in which measures 19 degrees and the hypotenuses 15 units long
Otrada [13]

Answer:



The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.

                     leg 1 = (15 units) x (cos 19) = 14.18 units

                     leg 2 = (15 units) x (sin 19) = 4.88 units

The lengths of the legs are 14.18 units and 4.88 units.  

8 0
3 years ago
The triangle and the trapezoid have the same area. Base b2 is twice the length of base b1. What are the lenghts of the bases of
Sati [7]

Answer:

<h2>The lengths of the bases of the trapezoid:</h2><h2>42/h cm and 84/h cm.</h2>

Step-by-step explanation:

The formula of an area of a triangle:

A=\dfrac{bh}{2}

<em>b</em><em> </em>- base

<em>h</em> - height

We have <em>b = 21cm, h = 6cm</em>.

Substitute:

A=\dfrac{(21)(6)}{2}=63\ cm^2

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

<em>b₁, b₂</em> - bases

<em>h</em><em> - </em>height

We have <em>b₁ = 2b₂</em>, therefore <em>b₁ + b₂ = 2b₂ + b₂ = 3b₂</em>.

The area of a triangle and the area of a trapezoid are the same.

Therefore

\dfrac{3b_2}{2}\cdot h=63         <em>multiply both sides by 2</em>

3b_2h=126          <em>divide both sides by 3</em>

b_2h=42         <em>divide both sides by h</em>

b_2=\dfrac{42}{h}

b_1=2b_2\to b_1=2\cdot\dfrac{42}{h}=\dfrac{84}{h}

8 0
3 years ago
Read 2 more answers
Alisha hiked a trail that was 9/10 mile and Joseph hiked a trail that was 5/10 mile. How much farther did Alisha hike than Josep
Elenna [48]

Answer:

4/10 or 2/5 of a mile more.

Step-by-step explanation:

Since the denominators are the same, all you have to do is subtract the numerators.

9-5=10.

Therefore, Alisha hiked 2/5 of a mile further than Joseph.

8 0
3 years ago
The area of a trapezoid is 33 square meters. one base is 4 meters long and the other base is 7 meters. find the height of the tr
In-s [12.5K]
h=6
A=((a=b)/2)h
33=((4+7)/2)h
33=(11/2)h
33=5.5h
6=h
7 0
3 years ago
Can someone please help me :)
gavmur [86]

Answer:

<em>90 degree</em>

Step-by-step explanation:

Three points A, B, and C are added and shown in attached picture.

As the property of inscribed angle in circle:

angle BAC = (1/2) x 88 = 44 deg

As the property of complement angle:

angle ABC = 180 - 89 = 91 deg

As the property of sum of three angles in a triangle:

angle ACB + angle ABC + angle BAC = 180 deg

=> angle ACB = 180 - angle ABC - angle BAC = 180 - 44 - 91 = 45 deg

One more time, we use the property of inscribed angle in circle:

x = 2 x angle ACB = 2 x 45 = 90 deg

Hope this helps!

7 0
3 years ago
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