<span>NaCl
First calculate the molar mass of NaCl and AgNO3 by looking up the atomic weights of each element used in either compound
Sodium = 22.989769
Chlorine = 35.453
Silver = 107.8682
Nitrogen = 14.0067
Oxygen = 15.999
Now multiply the atomic weight of each element by the number of times that element is in each compound and sum the results
For NaCl
22.989769 + 35.453 = 58.44277
For AgNO3
107.8682 + 14.0067 + 3 * 15.999 = 169.8719
Now calculate how many moles of each substance by dividing the total mass by the molar mass
For NaCl
4.00 g / 58.44277 g/mol = 0.068443 mol
For AgNO3
10.00 g / 169.8719 g/mol = 0.058868
Looking at the balanced equation for the reaction, there is a 1 to 1 ratio in molecules for the reaction. Since there is a smaller number of moles of AgNO3 than there is of NaCl, that means that there will be some NaCl unreacted, so the excess reactant is NaCl</span>
Answer:
option 1st is correct gains 1 electron and becomes a-1.
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B. SOLAR WIND
Answer:
2.5x10^–3 mole.
Explanation:
Data obtained from the question include:
Volume of solution = 25mL
Molarity of HNO3 = 0.1M
Mole of HNO3 =..?
First, we'll begin by converting 25mL to L. This can be achieved by doing the following:
1000mL = 1L
Therefore, 25mL = 25/1000 = 0.025L
Now, we can obtain the number of mole of HNO3 present in the solution as follow:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.1 x 0.025
Mole = 2.5x10^–3 mole.
Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.