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3 years ago

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PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

1 answer:

djverab [1.8K]3 years ago

7 0

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$0.442=\frac{x}{199.9}$

$x=88.4g$

Thus there are 88.4 g of calcium bromide.

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Answer:

A) An Alkaline

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2 years ago

A 50.0-g sample of liquid water at 25.0 Â°c is mixed with 23.0 g of water at 79.0 Â°c. the final temperature of the water is ___

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3 years ago

The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t

Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

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We are given:

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Putting values in above equation, we get:

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3 years ago

What is the [H+] of a solution with a pH of 6.6? Use a scientific calculator.

svetoff [14.1K]

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3 years ago

Read 2 more answers

A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will

Reil [10]

Answer:

The balanced chemical equation for this process:

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

$Molarity(M)=\frac{n}{V(L)}$

$n=m\times V=1.05 M\times 4,542 L=4,769.1 mol$

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

$\frac{1}{1}\times 4,769.1 mol=4,769.1 mol$ of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol 74 g/mol = 352,913.4 g

= $\frac{352,913.4 }{453.6} pounds =778.03 pounds$

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime = $0.25

Cost of 778.03 pounds of slaked lime = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.

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3 years ago