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PtichkaEL [24]
2 years ago
11

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

Chemistry
1 answer:
djverab [1.8K]2 years ago
7 0

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.442=\frac{x}{199.9}

x=88.4g

Thus there are 88.4 g of calcium bromide.

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<h3>What are the properties of group 2 elements?</h3>

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