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PtichkaEL [24]
3 years ago
11

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

Chemistry
1 answer:
djverab [1.8K]3 years ago
7 0

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.442=\frac{x}{199.9}

x=88.4g

Thus there are 88.4 g of calcium bromide.

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Which of the following would not be considered an observation in terms of the scientific method?
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the first option, tasting a pasta sauce after adding a new ingredient.

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Enter the balanced NET IONIC equation for the potentially unbalanced equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq).
Zigmanuir [339]

Answer:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Explanation:

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In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:

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2 years ago
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3 years ago
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Iridium has two naturally occurring isotopes, Iridium-191 and Iridium-193. If the average atomic mass of orodum s 192.217, what
Lina20 [59]

Answer:

The percent isotopic abundance of Ir-193 is 60.85 %

The percent isotopic abundance of Ir-191 is 39.15 %

Explanation:

we know there are two naturally occurring isotopes of iridium, Ir-191 and Ir-193

First of all we will set the fraction for both isotopes

X for the isotopes having mass 193

1-x for isotopes having mass 191

The average atomic mass is 192.217

we will use the following equation,

193x + 191(1-x) = 192.217

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(1-x)

1-0.6085 =0.3915

0.3915× 100= 39.15 %

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3 years ago
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