Question

PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic

Answer 1

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9  

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$0.442=\frac{x}{199.9}$

$x=88.4g$

Thus there are 88.4 g of calcium bromide.