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Yakvenalex [24]
3 years ago
10

Given their location on the periodic table, identify the ionic charge for each element and predict the compound formed by the ba

rium and chloride ions.
Chemistry
2 answers:
Maurinko [17]3 years ago
8 0
Barium has a 2+ charge as it is in group 2 in the periodic table and so it has two electrons in its outer shell and chloride has a -1 charge on its chloride ion. So we will need two of the chloride ions as we have a 2+ charge to match the amount of charge on one barium ion- forming barium ion

BaCI2
alexandr402 [8]3 years ago
5 0

Explanation:

Atomic number of barium is 56 and its electronic configuration is [Xe]6s^{2}.

Since, barium is a group 2 metal so in order to attain stability it will readily lose two electrons. Hence, barium will acquire a +2 charge and forms Ba^{2+} ion.

On the other hand, chlorine is a group 17 element and its electronic distribution is 2, 8, 7. Hence, to attain stability it will gain one electron and forms Cl^{-} ion.

Thus, we can conclude that charge on barium ion is +2 and charge on chlorine ion is -1.

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Answer:

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If you have a gold brick that is 2cm by 3cm by 4cm and has density of 19.3g/cm3, what is its mass?
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Volume = a x a x a  

V = 2 cm x 3 cm x 4 cm => 24 cm³

Density = 19.3 g/cm³

Mass = ?

Therefore:

m = D x V

m = 19.3 x 24

m = 463.2 g
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3 years ago
Ammonia can be produced in the laboratory by heating ammonium chloride
AnnyKZ [126]

Answer:

Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

Mass of ammonia produced = ?

Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

Number of moles of NH₄Cl:

Number of moles = mass/molar mass

Number of moles = 8.939 g / 53.5 g/mol

Number of moles = 0.17 mol

Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
2 years ago
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