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Yakvenalex [24]
3 years ago
10

Given their location on the periodic table, identify the ionic charge for each element and predict the compound formed by the ba

rium and chloride ions.
Chemistry
2 answers:
Maurinko [17]3 years ago
8 0
Barium has a 2+ charge as it is in group 2 in the periodic table and so it has two electrons in its outer shell and chloride has a -1 charge on its chloride ion. So we will need two of the chloride ions as we have a 2+ charge to match the amount of charge on one barium ion- forming barium ion

BaCI2
alexandr402 [8]3 years ago
5 0

Explanation:

Atomic number of barium is 56 and its electronic configuration is [Xe]6s^{2}.

Since, barium is a group 2 metal so in order to attain stability it will readily lose two electrons. Hence, barium will acquire a +2 charge and forms Ba^{2+} ion.

On the other hand, chlorine is a group 17 element and its electronic distribution is 2, 8, 7. Hence, to attain stability it will gain one electron and forms Cl^{-} ion.

Thus, we can conclude that charge on barium ion is +2 and charge on chlorine ion is -1.

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If you put a plant across the room from a window, how will this affect the growth of the plant?
grin007 [14]
The plant will grow towards the light source.
3 0
3 years ago
How much heat is lost when 0.440 mol of steam condenses at 100 °C?
dusya [7]

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

Q=n\lambda_v

where

n is the number of moles of the substance

\lambda_v is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

\lambda_v=40,660 J/mol is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

Q=(0.440)(40660)=17,890 J

8 0
4 years ago
When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ
Naddik [55]
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
        
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute: 
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025=  0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
 = 0.0075 * 63.546 =0.477 g


3 0
3 years ago
two samples of water, 10 grams and 50 grams are in sperate cups which of the following properties is different for the two boili
Trava [24]

Answer:

volume

Explanation:

The volume of the two samples of water will be different because volume is the amount of space occupied by a body. It is dependent on the amount of materials it contains.

  • The 50g sample will have a higher volume compared to the 10g sample.
  • The boiling point and density are intensive properties and do not depend on the amount of matter present.
  • Since both samples are from the same source, they will have the same color.
7 0
3 years ago
Read 2 more answers
A molecule has sp2 hybridization with 1 lone pair.... The electron pair geometry of this molecule is: ... The geometry of this m
MrRa [10]

Answer:

The electron pair geometry is Trigonal planar

Molecular geometry - Bent

Approximate bond angle - <120°

Explanation:

The valence shell electron pair repulsion theory enables us to predict the shapes of molecules based on the number of electron pairs present on the valence shell of the central atom and based on the hybridization state of the central atom.

sp2 hybridization corresponds to trigonal planar geometry. Let us recall that the presence of lone pairs causes a deviation of the molecular geometry from the expected geometry based on the number of electron pairs.

Hence, owing to one lone pair present, the observed molecular geometry is bent.

6 0
3 years ago
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