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Morgarella [4.7K]
3 years ago
5

With a force of 5 newtons, Amanda pushes the stack of books to the right. At the same time, Jeremy, her little brother, pushes t

he stack of books to the left with a force of 10 newtons.
Chemistry
2 answers:
Allisa [31]3 years ago
5 0

Answer:

A.  5 N to the left

<em>Note: The question is incomplete. The complete question is given below:</em>

<em>With a force of 5 newtons, Amanda pushes the stack of books to the right. At the same time, Jeremy, her little brother, pushes the stack of books to the left with a force of 10 newtons. </em>

<em>What is the direction and magnitude of the resulting force? </em>

<em>A.  5 N to the left </em>

<em>B.  5 N to the right </em>

<em>C.  10 N to the right </em>

<em>D.  10 N to the left </em>

Explanation:

Forces are vector quantities.

Vector quantities are quantities that can be represented both in magnitude and direction.

Forces have both magnitude and direction. Forces can be directed positively or negatively.

For example, in the question above, if forces acting to the right are considered to be in the positive direction, forces acting to the left are considered to be acting in a negative direction.

In the addition of forces, both their magnitude and direction are taken into consideration.

In the example above, taking forces acting to the right as positive and to the left as negative, the sum of the forces is:

Resultant force, F = (5 N) + (-10N)

F = -5 N

Therefore, the net force is 5 N and is directed towards the left

Natali [406]3 years ago
3 0

Answer:

5 N to the left

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What is the concentration in g/L of a solution containing 10 g of solute in 2 L of solution
alekssr [168]

The concentration is 5 g/L.

Concentration = mass/volume = 10 g/2 L = 5 g/L

6 0
3 years ago
How many moles of sodium carbonate contain 1.773 × 1017 carbon atoms?
vesna_86 [32]

Answer:

  • 2.941 × 10⁻¹⁷ mol

Explanation:

1) Chemical formula of sodium carbonate: <em>Na₂CO₃</em>

2) Ratio of carbon atoms:

  • The number of atoms of C in the unit formula Na₂CO₃ is the subscript for the atom, which is 1 (since it is not written).

Hence, the ratio is 1 C atom / 1 Na₂CO₃ unit formula.

This is, there is 1 atom of carbon per each unit formula of sodium carbonate.

3) Calculate the number of moles in 1.773 × 10⁷ carbon atoms

  • Divide by Avogadro's number: 6.022 × 10²³ atoms / mol

  • number C moles  = 1.773 × 10⁷ atoms / (6.022 × 10²³ atoms/mol)

  • number C moles = 2.941 × 10⁻¹⁷ mol

Since, the ratio is 1: 1, the number of moles of sodium carbonate is the same number of moles of carbon atoms.

5 0
3 years ago
Which of the following is evidence that groundwater cause erosion and deposition
defon

Answer:You didn't provide examples

Explanation: Groundwater can cause erosion under the surface as it moves through the soil. During the movement an acid is formed which what causes erosion and deposition.

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4 0
3 years ago
A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc
Elan Coil [88]

Answer:

a. Moles of NaOH  = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

a.

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For NaOH :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of NaOH :

Moles=0.1052 \times {15.62\times 10^{-3}}\ moles

Moles of NaOH  = 0.001643 moles

b.

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

c.

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains \frac{0.296}{1.159}\times 1.213 g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0
3 years ago
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