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faltersainse [42]
3 years ago
10

What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo

n ingredient in plaster
Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

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A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :

The percent yield of the product is 83.0%

The actual yield of the product is 14.2 grams.

<h3>Percentage Yield:</h3>

Percent yield is the percent ratio of actual yield to the theoretical yield.

Mathematically,

percent yield = actual yield / theoretical yield x 100%

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percentage yield = 14.2 / 17.1 × 100%

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The percent yield of the product is 83.0%

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learn more on percentage yield here; brainly.com/question/4180677

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