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maksim [4K]
4 years ago
7

Oliver shot 8 free throws at practice, making 6 free throws and missing 2 free throws. If Oliver is equally likely to make a fre

e throw as he is to miss a free throw, find the probability of this outcome by expanding (m+n)8.
Mathematics
2 answers:
jek_recluse [69]4 years ago
7 0

Answer: Then you turn the 6 to a 4 and the 2 into a 4 also. Because Oliver wanted the free throw and the free throw he missed turn both equal so you divide 8 with 2 and get 4.

Hatshy [7]4 years ago
6 0

Answer:

Alfredjiang2010 is a very smart person and his answer is correct I think.

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HELP!!
maksim [4K]
Equation: 4x+15=31
I have included a picture of my work since explaining might be difficult but the way I solved this if the beginning of algebra and I hope it makes sense.
Your welcome, Katy

8 0
4 years ago
Bruce saved $35.00 to buy a new video game . The game's original price was $42.00, but it was on sale for 30% off. The sales tax
fenix001 [56]

Answer:

The answer to your question is Yes, he can buy it.

Step-by-step explanation:

Data

Money saved = $35

Original Price = $42

Discount = 30%

Tax = 5 %

Process

1.- Calculate the price of the Video game with the discount

                    $42 --------------------- 100%

                         x  ---------------------   30%

                         x = (30 x 42) / 100

                         x = $ 12.6

   Price with discount = 42 - 12.6

                                    = $ 29.4

2.- Calculate the price of the Video game plus taxes

                      $29.4 ------------------- 100%

                          x      -------------------    5%

                          x = (5 x 29.4) / 100

                          x = 147 / 100

                          x = 1.47

    Price plus taxes = 29.4 + 1.47

                                = $ 30.87

3.- Conclusion

Bruce can buy the Video game because he saved $35 and the video game plus taxes cost $30.87.  

8 0
3 years ago
The desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5
LekaFEV [45]
Given that t<span>he desired percentage of sio2 in a certain type of aluminous cement is 5.5. to test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. suppose that the percentage of sio2 in a sample is normally distributed with σ = 0.32 and that \bar{x}=5.24.

</span>
<span>To investigate whether this indicate conclusively that the true average percentage differs from 5.5.



Part A:

From the question, it is claimed that </span><span>t<span>he desired average percentage of sio2 in a certain type of aluminous cement is 5.5</span></span> and we want to test whether the information from the random sample <span>indicate conclusively that the true average percentage differs from 5.5.

Therefore, the null hypothesis and the alternative hypothesis is given by:

H_0:\mu=5.5 \\  \\ H_a:\mu\neq5.5



Part B:

The test statistics is given by:

z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}}  \\  \\ =\frac{5.25-5.5}{0.32/\sqrt{16}} \\  \\ = \frac{-0.25}{0.32/4} = -\frac{0.25}{0.08}  \\  \\ =-3.125



Part C:

The p-value is given by

P(z\ \textless \ -3.125)=1-P(z



Part D:

Because the p-value is less than the significant level α, we reject the null hypothesis and conclude that "</span><span>There is sufficient evidence to conclude that the true average percentage differs from the desired percentage."



Part E:

</span>If the true average percentage is μ = 5.6 and a level α = 0.01 test based on n = 16 is used, what is the probability of detecting this departure from H0? (Round your answer to four decimal places.)

The probability of detecting the departure from H_0 is given by

1-\phi\left(z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right)+\phi\left(-z_{1-\frac{\alpha}{2}}+ \frac{\mu_0-\mu_1}{\sigma/\sqrt{n}} \right) \\  \\ =1-\phi\left(z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right)+\phi\left(-z_{1-\frac{0.01}{2}}+ \frac{5.5-5.6}{0.32/\sqrt{16}} \right) \\  \\ =1-\phi\left(z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)+\phi\left(-z_{1-0.005}+ \frac{-0.1}{0.32/4} \right)

=1-\phi\left(z_{0.995}+ \frac{-0.1}{0.08} \right)+\phi\left(-z_{0.995}+ \frac{-0.1}{0.08} \right) \\  \\ =1-\phi(2.576-1.25)+\phi(-2.576-1.25) \\  \\ =1-\phi(1.326)+\phi(-3.826) \\  \\ =1-0.90758+0.00007 \\  \\ =0.0925



Part F:

What value of n is required to satisfy α = 0.01 and β(5.6) = 0.01? (Round your answer up to the next whole number.)

The value of n is required to satisfy α = 0.01 and β(5.6) = 0.01 is given by

n=\left[ \frac{\sigma(z_{0.005}+z_{0.01})}{\mu_0-\mu} \right]^2 \\  \\ = \left[\frac{0.32(-2.576-2.326)}{5.5-5.6} \right]^2 \\  \\ =\left[\frac{0.32(-4.902)}{-0.1} \right]^2=\left[\frac{-1.56864}{-0.1} \right]^2 \\  \\ =(15.6864)^2=247
3 0
4 years ago
Solve for q.<br><br> 20 − 3q = 5q − 20
galina1969 [7]

Answer:

q = 5

Step-by-step explanation:

40 - 3q = 5q

40 = 8q

5 = q

7 0
4 years ago
Read 2 more answers
Given ABCDEF ≅ GHIJKL .
svetlana [45]
114

A would equal G, B would equal H, C to I, D to J, E to K, and F to L. 
5 0
3 years ago
Read 2 more answers
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