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tatyana61 [14]
3 years ago
7

Round 963 to 1 significant figure.

Mathematics
1 answer:
dedylja [7]3 years ago
7 0
963 would be rounded to become 1000.
This is because 9 is the first non-zero number and so since there are only going to be 1 significant figures, the 9 would round up or down. There is a 6 after the 9, so it rounds up to 10, making it 1000.
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I NEED SERIOUS HELP PLEASE WITH PROBABILITY
erastova [34]
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and since the dice has the numbers 1, 2, 3, 4, 5 and 6 on it the probability for the even and the odd numbers are the same the even being 2, 4, 6  and odd being 1, 3, 5. the probability is 3/6 or simplified 1/2.
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Answer:

25.4

Step-by-step explanation:

1/3 ( 2.55+.75) +3* 8.1

Using pemdas, parentheses first

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2 years ago
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Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
2 years ago
Solve by Elimination<br> b) -4x+2y=-4<br> 4x-5y=-8
ruslelena [56]

Answer:

x = 3

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by elimination,

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-4x+2y + 4x-5y = -4 -8

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-4x+2y=-4   -----(eq1), when y = 4,

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-4x= -4   - 8

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x = -12 / (-4) = 3

5 0
3 years ago
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