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lara [203]
2 years ago
6

What is the volume of this figure need help asap!!!

Mathematics
2 answers:
frutty [35]2 years ago
5 0

Answer:

Volume of the figure= 312 yd²

Step-by-step explanation:

Okay let's split this figure up into two different rectangles. Let's draw the line at the part of the rectangle that is nearest us (looking at the picture). The little part where it says 6 yd. and 4 yd.

We know volume is V= lwh

Start with the main rectangle (bigger one)

I see l=12, w=11, and h=2

So V(of main rectangle)=12x11x2

V(of main rectangle)=264

We have to go do the smaller rectangle now

I see l=4, w=6, but I know the h=2 because the height is the same as the main triangle.

So V(of smaller rectangle)=6x4x2

V(of smaller rectangle)=48

Now knowing the volume of the main and smaller rectangle, we have to add them to find the volume of the figure.

V(of smaller rectangle) + V(of main rectangle)

264 + 48

Volume of the figure= 312 yd²

ratelena [41]2 years ago
4 0

Answer:

312

Step-by-step explanation:

We can calculate by dividing it into 2 parts. The first part has length of 6, width of 4 and height of 2, so volume of this part is 48. Similarly, we can calculate that the volume of the second part is 264. Hence, the total volume is 312.

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how could you estimate the volume of the box if you didn't know anything except the volume of the cylinder inside it?
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Answer:

Step-by-step explanation:

Since the box contains a cylinder, the height of the box must be gt; = cylinder height

And the area at the bottom of the box is definitely larger than the area at the bottom of the cylinder.

The area at the bottom of the cylinder is PI r squared,

If the bottom of the box is a square, then the area of the bottom is 4r^2, whereas the bottom tends to be polygon, which is equivalent to cutting the circle into equal parts by circle cutting.

So the area at the bottom of the box is \lim_{ Number of polygon edges\to \infty} \pi r^{2},

It follows that the volume of the box is greater than the volume of the cylinder

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3 years ago
What equation could be used to solve for the length of XY?
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The as were is XY=22/sin(4)
8 0
3 years ago
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Answer is B.

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5 0
3 years ago
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The probability of rain on the last day of July is 95 % . If the probability remains constant for the first seven days of August
8090 [49]

The probability that it rains at most 2 days is 0.00005995233 and the variance is 0.516

<h3>The probability that it rains at most 2 days</h3>

The given parameters are:

  • Number of days, n = 7
  • Probability that it rains, p = 95%
  • Number of days it rains, x = 2 (at most)

The probability that it rains at most 2 days is represented as:

P(x ≤ 2) = P(0) + P(1) + P(2)

Each probability is calculated as:

P(x) = ^nC_x * p^x * (1 - p)^{n - x}

So, we have:

P(0) = ^7C_0 * (92\%)^0 * (1 - 92\%)^{7 - 0} = 0.00000002097

P(1) = ^7C_1 * (92\%)^1 * (1 - 92\%)^{7 - 1} = 0.00000168821

P(2) = ^7C_2 * (92\%)^2 * (1 - 92\%)^{7 - 2} = 0.00005824315

So, we have:

P(x ≤ 2) =0.00000002097 + 0.00000168821 + 0.00005824315

P(x ≤ 2) = 0.00005995233

Hence, the probability that it rains at most 2 days is 0.00005995233

<h3>The mean</h3>

This is calculated as:

Mean = np

So, we have:

Mean = 7 * 92%

Evaluate

Mean = 6.44

Hence, the mean is 6.44

<h3>The standard deviation</h3>

This is calculated as:

σ = √np(1 - p)

So, we have:

σ = √7 * 92%(1 - 92%)

Evaluate

σ = 0.718

Hence, the standard deviation is 0.718

<h3>The variance</h3>

We have:

σ = 0.718

Square both sides

σ² = 0.718²

Evaluate

σ² = 0.516

This represents the variance

Hence, the variance is 0.516

Read more about normal distribution at:

brainly.com/question/4079902

#SPJ1

7 0
1 year ago
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