You can reword the two equations as:
-5x-y=15 (Divide original value by 3)
-2x+6y=6
Then use elimination to find x:
-30x-6y=90 (Multiply by 6 to get y values to be same to cancel out)
-2x+6y=6
You're left with:
-32x=96. Which can then be solved to find x which is -3.
Then plug back in
-2x+6y=6
Now to: -2(-3)+6y=6.
Which reduces to 6+6y=6. So y=0.
To graph them, just reword the equations (yes once again) so that y is in front.
y=-5x-15 and y=(1/3)x+1
Answer:
x: -2
f(x): 1.5
x: 0
f(x): 0.5
x: 3
f(x): -1
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
the variable cannot have a negative symbol, unless it has no number.
Answer:
<em>y = (-4/3)*x + 7</em>
<em />
Step-by-step explanation:
The point-slope form of the equation of a line is: <em>y = a*x + b </em>
In the above equation, <em>a </em>is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]
The given line has a slope of -4/3, so that <em>a = -4/3 </em>
=> The equation of this line has a form as following: <em>y = (-4/3)*x + b (1)</em>
<em />
As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:
<em>y = (-4/3)*x + b</em>
<em>=> -5 = (-4/3)*9 + b </em>
<em>=> -5 = -12 + b </em>
<em>=> b = 7</em>
<em />
So that the equation in point-slope form of the given line is:
<em>y = (-4/3)*x + 7</em>
<em />
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
