Answer:
90 between 1000 and 9999
Step-by-step explanation:
The first digit cannot be 0. It can be nine other digits.
The second digit can be anything between 0 and 9.
To be palindromic the 2nd and 3rd digits must be the same.
And in addition, the 1st and 4 numbers must be the same.
So the answer is 9 * 10 = 90. That does seem too small, but try making a palindrome with the restrictions I have outlined. None of the examples you have given beginning with 8 are palindromic.
8118 is palindromic
8998 is also palindromic
9009 is palindromic
2002 is palindromic
There are only 90 of them.
There is 6 regular packs and 6 value packs so add those (6+6=12). Divide 12 by 2 (because there's 2 socks in a pair) and get 6. Then divide 402 by 6 and get 67 pairs. Do the same for the second location.
Y=5 -- x =17
so y= 5*10/17= 50/17 when x = 10
<u>Given</u>:
Given that the first term of the geometric sequence is 729.
The common ratio is 
We need to determine the seventh term of the sequence.
<u>Seventh term</u>:
The seventh term of the sequence can be determined using the formula,
To find the seventh term, let us substitute n = 7 in the above formula, we get;
Now, substituting 
and 
, we get;
Thus, the seventh term of the geometric sequence is 1.
3x+21-12=8x-28
collect the like terms
3x-8x=-28(21-12=9)
-5x=-28-9
-5x=-37
x=7.4
