All categories

3 years ago

9 - x < -11 lololol help

Mathematics

1 answer:

Evgen [1.6K]3 years ago

8 0

Answer:

Hey! Your answer is , x >20

Step-by-step explanation:

Hope this helps! :)

Have a nice day!

You might be interested in

Match the numbers in scientific notation with the corresponding numbers in standard notation. 2.32E9

andre [41]

Complete question :

Match the numbers in scientific notation with the corresponding numbers in standard notation.

232,000,000

0.00000431

2,320,000,000

0.000000000000431

2.32E9

2.32E8

4.31E-13

4.31E-6

Answer:

2.32E8 = 232,000,000

2.32E9 = 2,320,000,000

Step-by-step explanation:

2.32E8 - - > 8 digits after the decimal point ; 232,000,000

2.32E9 - - > 9 digits after the decimal point ;

2,320,000,000

4.31E-13 - - > 13 preceeding 0's before digit '4' ; 0.000000000000431

4.31E-6 - - > 6 preceeding 0's before digit '4' ; 0.000000000000431

8 0

3 years ago

A snowboard originally costs $120, but it is on sale for 45% off. If a customer buying the snowboard has a coupon for $15.00 off

kotykmax [81]

51 dollars hope that helps

7 0

3 years ago

Read 2 more answers

Dan invests £3400 into his bank account.

Temka [501]

Answer: £4597.82

Step-by-step explanation:

5 0

3 years ago

Help me !!!!!!!!!!!!!!!!!!!!!!

Sveta_85 [38]

Answer:4/125

Step-by-step explanation:

5 0

3 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

3 years ago