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3 years ago

Which graph represents y=3(x-3)^2+3

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

Graph y = (–5/3)x – 2.

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Write 4.625 as a mixed number in simplest form

Zarrin [17]

4 625/1,000 to 4 25/40 to 4 5/8

4 0

3 years ago

Is the point P (2,8) on the inside or outside of the circle described with equation x^2+y^2=100?

kykrilka [37]

Points $(x,y)$ on the circle satisfy $x^2+y^2=100$ .

Points inside the circle satisfy $x^2+y^2$ .

Points outside the circle satisfy $x^2+y^2>100$ .

We have

$2^2+8^2=4+64=68$

so the point (2, 8) lies inside the circle.

6 0

3 years ago

What relationship do the ratios of sin x° and cos y° share?

puteri [66]

Answer:

The ratios are both identical (3/5 and 3/5).

Step-by-step explanation:

sin x° is equivalent to O/H, or the opposite/hypotenuse sides of the triangle. Therefore:

sin x° = 3/5.

cos y° is equivalent to A/H, or the adjacent/hypotenuse sides of the triangle.

cos y° = 3/5.

$\frac{3}{5} =\frac{3}{5}$

The ratios are identical.

8 0

3 years ago

What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7

Nat2105 [25]

Consider the given equations:

The first equation is as:

$\frac{5}{7} \div \frac{1}{3} = ?$

So, $\frac{5}{7} \div \frac{1}{3}$

= $\frac{5}{7} \times \frac{3}{1}$

Multiplying the given fractions, we get as

= $\frac{15}{7}$

Now, consider the second equation as:

$? \times \frac{1}{3} = \frac{5}{7}$

Multiplying by '3' to both the sides of the equation, we get

$? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}$

$? = \frac{15}{7}$

So, the number which best completes both the equations is $\frac{15}{7}$ .

6 0

3 years ago

Twenty-four distinguishable balls are to be placed in six boxes.(DIFFERENT BOXES) (a) In how many different ways can this be don

zvonat [6]

Answer: a) 124,596, b) 2142691552.

Step-by-step explanation:

Since we have given that

Number of distinguishable balls = 24

Number of boxes = 6

(a) In how many different ways can this be done?

$^{24}C_6\\\\=134,596$

(b) In how many different ways can this be done if box 1 must get 12 balls, box 2 must get 7 balls, box 3 must get 5 balls, and boxes 4, 5, and 6 must be empty?

Number of ways would be

$\dfrac{24!}{12!7!5!}=2142691552$

Hence, a) 124,596, b) 2142691552.

3 0

3 years ago