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2 years ago

11

Judy and Ramey together have 42 stuffed animals. Judy has 12 fewer animals than Ramey. How many stuffed animals does each girl h

ave? help me pls

1 answer:

Art [367]2 years ago

7 0

Answer: Ramey has 27 and Judy has 15

Step-by-step explanation:

Just bc 27 + 15 is 42

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2=6<br> 3=12<br> 4=20<br> 5=30<br> 6=42<br> 9=?

REY [17]

It is a pattern so 2*3=6
3 times 4 is 12
4 times 5 is 20
5 times 6 is 30
6 times 7 is 42
so, 9 times 8 is 72.

please vote as brainliest

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2 years ago

Your drapery business has just gotten a new client who needs 4 drapes made. Each one will need to be 8 feet by 5 feet and you mu

UNO [17]

22 because 6 inches on top and bottom means you need 12 inchesw each drape and you have 4 drapes so 48 inches therefor rounding that you get 1 yard each added onto the 8 feet and 5 feet for each drape.

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3 years ago

I need help with this problem

Misha Larkins [42]

I think first 80 and second 90

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2 years ago

calculate the means and the standard deviation of the following set of data 4.578g, 4.581g, 4.572g, 4.573g, 4.601g, 4.577g. stat

AfilCa [17]

Answer:

68% Confidence interval = [4.5752, 4.5848]

95% Confidence interval = [4.5688, 4.5918]

Step-by-step explanation:

Sample mean (X) = 4.580

Sample Standard Deviation (S) = 0.01065

Sample size (n) = 6

$T_{(5)}$ for alpha/2 0.84 = 1.1037

$T_{(5)}$ for alpha/2 0.975 = 2.5706

68% Confidence interval = $[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}]$ = [4.5752, 4.5848]

95% Confidence interval = $[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}]$ = [4.5688, 4.5918]

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3 years ago

ILL MARK AS BRAINLEST

devlian [24]

Answer:

im pretty sure the answer is c

7 0

3 years ago