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1 year ago

Helppp!! Instructions: Find the missing side. Round your answer to the nearest tenth.

Mathematics

1 answer:

natita [175]1 year ago

4 0

Answer:

x ≈ 14.4

Step-by-step explanation:

using the cosine ratio in the right triangle

cos59° = $\frac{adjacent}{hypotenuse}$ = $\frac{x}{28}$ ( multiply both sides by 28 )

28 × cos59° , then

x ≈ 14.4 ( to the nearest tenth )

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Mary rolls two dice. She adds the numbers on the two dice. What is the chance of this sum being twelve?

jonny [76]

Answer:

10%

Step-by-step explanation:

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3 years ago

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Which shows the given inequalities in slope-intercept form?

yanalaym [24]

Answer: Solve for X

4x−5y<1

Step-by-step explanation:

step 1 add 5y to each side

4x−5y+5y<1+5y

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Step 2: Divide both sides by 4.

4x4<5y+14

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Answer:

x<54y+14

Let's solve for x.

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Step 1: Add (-1)/2y to both sides.

−x+12y+−12y<3+−12y

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Step 2: Divide both sides by -1.

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Answer:

x>12y−3

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3 years ago

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3 years ago

How I Devide in long Division all steps?

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3 years ago

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Current government spending to fund public schools is about 6×1011 dollars per year. The average cost nationally for a student t

NeX [460]

60000000 students can attend public schools with the current funding

<em><u>Solution:</u></em>

Given that Current government spending to fund public schools is about $6 \times 10^{11}$ dollars per year

The average cost nationally for a student to attend a public school for a year is about $10,000

To find: number of students can attend public schools with the current funding

$\text{ current funding } = 6 \times 10^{11} \text{ dollars}$

$\text{ average cost for 1 student } = 10000 \text{ dollars }$

Therefore,

$\text{ number of students } = \frac{\text{ current funding }}{\text{ average cost of 1 student}}$

Substituting the values we get,

$\text{ number of students } = \frac{6 \times 10^{11}}{10000}\\\\\rightarrow \frac{6 \times 10^{11}}{10000} = \frac{6 \times 10^{11}}{10^4}\\\\\rightarrow \frac{6 \times 10^{11}}{10^4} = 6 \times 10^{11-4} = 6 \times 10^7\\\\\rightarrow 6 \times 10^7 = 60000000$

Thus 60000000 students can attend public schools with the current funding

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3 years ago